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Straight-Line Graphs

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Cambridge (CIE) IGCSE · Additional Maths

Straight-Line Graphs

Big idea: Every straight line has exactly one "steepness" (gradient) and one starting height (y-intercept) — once you know two points, or one point and the steepness, you can write down the line's entire equation and answer almost any question about it.

OverviewEverything in this chapter, at a glance
  • The gradient m of a line measures its slope: m = (y₂−y₁)/(x₂−x₁)
  • Three ways to write a line's equation: y = mx + c (gradient-intercept), y − y₁ = m(x − x₁) (point-gradient), and ax + by + d = 0 (general form)
  • The midpoint of two points is just the average of their x's and the average of their y's
  • The length of a line segment comes from Pythagoras: d = √[(x₁−x₂)² + (y₁−y₂)²]
  • Parallel lines have the exact same gradient (m₁ = m₂)
  • Perpendicular lines have gradients that multiply to −1 (m₁ × m₂ = −1) — i.e. they're negative reciprocals of each other
Topic 1Finding the Gradient of a Straight Line

What "gradient" actually means

Think of the gradient as the answer to the question: "For every step I take to the right, how much does the line go up (or down)?" It's a single number that completely describes how steep and in which direction a line tilts.

A gradient of 1 means: move 1 unit right → the line rises 1 unit. A gradient of −2 means: move 1 unit right → the line falls 2 units (the negative sign tells you it's going downhill as you move right). The bigger the number (ignoring the sign), the steeper the line. A gradient of 0 means the line is perfectly flat (horizontal).

y | * (x2, y2) | .·" | .·" | | .·" | dy (change in y) | .·"________| | .·" dx | .·" (change in x) |·* (x1, y1) +------------------------------ x
m = (y₂ − y₁) / (x₂ − x₁)
gradient = (difference in y) ÷ (difference in x) — often remembered as "rise over run"
⚡ Why this formula works It's literally just the definition of slope from real life — how much height you gain (dy) for how much distance you travel horizontally (dx). It doesn't matter which point you call (x₁,y₁) and which you call (x₂,y₂), as long as you're consistent — subtract in the same order top and bottom.
Worked Example
Find the gradient of the line through (−2, 6) and (8, 1).
m = (6 − 1) / (−2 − 8)
m = 5 / (−10)
Practice Question 1
Find the gradient of the line passing through (3, −1) and (7, 9).
Practice Question 2
A line passes through (−4, 5) and (2, 5). What is its gradient, and what does this tell you about the line?
Topic 2The Three Equations of a Straight Line

  y = mx + c — Gradient-Intercept Form

This is the most useful form because you can read the gradient and y-intercept straight off it — no rearranging needed. Here, m is the gradient, and c is the y-intercept, meaning the line crosses the y-axis at the point (0, c).

y = mx + c
m = gradient · c = value of y when x = 0 (where the line crosses the y-axis)

  y − y₁ = m(x − x₁) — Point-Gradient Form

building

y − y₁ = m(x − x₁)
💡 The strategy examiners expect
Topic 3
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Also in the full note
  • ax + by + d = 0 — General Form
  • Finding an equation from scratch — the full method
  • Just an average of the coordinates
  • It's really just Pythagoras in disguise
  • Same steepness, never meet
  • Meeting at a perfect right angle
  • Mistakes students actually make
  • What examiners are looking for
What's inside
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