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O Level · International Mathematics 0607

Trigonometric Graphs & Equations

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Cambridge (CIE) IGCSE — International Maths: Extended

Trigonometric Graphs & Equations

The big idea: sin, cos and tan graphs are just repeating waves (or repeating branches, for tan) — once you know their shape, their period, and their symmetry, you can solve any trig equation just by sketching, without needing to "guess" answers.

SummaryEverything in this chapter, at a glance
  • y = sin x and y = cos x are smooth waves that oscillate between 1 and −1, repeating every 360°.
  • y = tan x is not a wave — it's a series of repeating branches shooting from −∞ to +∞, with a period of only 180°, separated by vertical asymptotes.
  • Amplitude = half the vertical distance from max to min (how "tall" the wave is).
  • Period = the horizontal distance for one full repeat (how "wide" one cycle is).
  • For y = a sin(bx) or y = a cos(bx): a controls amplitude, b controls period via period = 360°/b.
  • To solve trig equations: find one solution with your calculator's inverse function, then use the graph's symmetry (sin/cos) or periodicity (tan) to find every other solution in the given range.
1. Trigonometric GraphsWhat sin, cos, and tan actually look like

What are trig graphs, really?

Up until now you've probably only used sin, cos and tan for right-angled triangles, where the angle has to be somewhere between 0° and 90° (it can't be obtuse or you don't have a triangle anymore!). Trig graphs free the angle from that restriction. Here, x is just a number that represents an angle — and it can be obtuse (90°–180°), reflex (180°–360°), or even negative or bigger than 360°. The graphs show you what sin, cos and tan do across the whole range of angles, not just the acute ones.

The key thing that makes these graphs special is that they're periodic — the shape repeats itself forever in both directions. Think of a running track: once you've gone all the way round, you're back exactly where you started, and the next lap looks identical to the last one. That's exactly what sin and cos do every 360°.

The graph of y = sin x

y = sin x is a smooth wave. It passes through the origin (0, 0), rises to a maximum height of 1 at x = 90°, comes back down through 0 at x = 180°, dips to a minimum of −1 at x = 270°, and returns to 0 at x = 360° — then the whole pattern repeats.

x: 0° 90° 180° 270° 360° 450° y: 0 1 0 -1 0 1 1 | ___ | / \ 0.5 | / \ 0 |__/_____________\____________ x |0 90 180 270 \ 360 450 -0.5 | \ / -1 | \_ _ /
Key features of y = sin x Passes through (0, 0)  •  Amplitude = 1  •  Period = 360° In plain words: it starts at the middle, swings up to 1, back down through the middle to −1, then back up — one full "swing cycle" every 360°.

The graph of y = cos x

y = cos x is exactly the same wave shape as sin x — same amplitude, same period — just shifted. Instead of starting at 0, it starts at its maximum: the y-intercept is (0, 1). It dips to −1 at x = 180°, and comes back up to 1 at x = 360°.

A really useful way to remember the relationship: cos x is just sin x shifted 90° to the left. If you slide the sin graph left by a quarter of a cycle, you get the cos graph exactly. This connection comes up a lot in later topics, so it's worth internalising now rather than just memorising two separate shapes.

Key features of y = cos x Y-intercept at (0, 1)  •  Amplitude = 1  •  Period = 360° In plain words: it starts at the top of the wave, dips down to the bottom by the halfway point, then climbs back to the top — same rhythm as sin x, just starting in a different place.

The graph of y = tan x

Tan behaves completely differently from sin and cos, and this trips a lot of students up. It is not a smooth wave — it's made of separate curved "branches." Each branch starts down near −∞, climbs up through the origin (or through a repeat of it), and shoots up towards +∞ — then suddenly a new branch starts again.

The vertical dashed lines the branches never quite touch are called asymptotes. They occur at x = 90°, x = 270°, and so on (every 180°, since tan repeats twice as fast as sin and cos). The curve gets closer and closer to these lines but mathematically can never touch them — this is because tan x = sin x / cos x, and when cos x = 0 the fraction is undefined (you can't divide by zero!). That's exactly why the asymptotes sit at 90°, 270°, etc. — those are the angles where cos x = 0.

2 | | | | | /| /| /| 1 | / | / | / | | / | / | / | 0 |/___|__/___|__/___|______ x |0 90 180 270 360 -1 | / | / | / | | / | / | / | -2 |/ | / | / | asymptote asymptote at x=90° at x=270°
Key features of y = tan x Passes through (0, 0)  •  No amplitude (goes from −∞ to +∞)  •  Period = 180°  •  Asymptotes at x = 90°, 270°, 450°... In plain words: it's a set of steep, repeating S-shaped branches, walled off by invisible vertical lines it can never cross.
Why does this matter? Because tan has no amplitude and half the period of sin/cos, questions love testing whether you can tell the three graphs apart just from a picture — e.g. "is this a tan graph or a sin graph?" Look for asymptotes (only tan has them) and check whether it touches a maximum/minimum (only sin/cos do).
Practice Question

A graph passes through the origin, has no maximum or minimum value, and has vertical asymptotes at x = 90° and x = 270°. Which trig graph is it, and what is its period?

Practice Question

Explain, using a key feature of each graph, why y = sin x cannot be the same graph as y = cos x, even though both are waves with amplitude 1 and period 360°.

2. Periods & AmplitudesMeasuring the "size" and "speed" of a wave

What are oscillating graphs?

Sine and cosine are called oscillating graphs because they swing back and forth (oscillate) between a highest point and a lowest point, over and over, forever in both directions along the x-axis. A full "swing" from start back to the same point is called one cycle.

Amplitude

The amplitude is half the vertical distance between the maximum point and the minimum point. Picture the horizontal line running exactly through the middle of the wave (often the x-axis itself) — the amplitude is simply how far the wave reaches above (or below) that middle line.

For the basic graph y = sin x, the wave goes up to 1 and down to −1, so the amplitude is 1 (it reaches exactly 1 unit above and below the middle line, y = 0).

Period

The period is the horizontal distance you need to travel along the x-axis before the graph starts repeating itself exactly. You can measure it several equivalent ways: from one maximum point to the next maximum point, from one minimum to the next minimum, or from one x-intercept to the x-intercept two crossings later (skipping the one in between).

For y = cos x, the period is 360° — go 360° along the x-axis from any point on the curve, and you land on an identical point.

Analogy that helps Think of amplitude as the height of a Ferris wheel's swing (how far up and down you go), and period as how long one full rotation takes. A taller wheel = bigger amplitude. A faster wheel = shorter period. They're independent of each other — you can change one without touching the other.

Sketching graphs from their equation

Oscillating functions are usually written in the form f(x) = a sin(bx) or f(x) = a cos(bx). The two letters a and b each control a completely different feature of the graph — don't mix them up!

What "a" does — controls amplitude (height)

a is the amplitude directly. The bigger |a| is, the taller the wave — it stretches the whole graph vertically. For example, in y = 5cos x, the amplitude is 5: the wave now swings between 5 and −5 instead of between 1 and −1.

If there's a number added on outside the trig function too — like y = 2 + (1/5)cos x — that number (2) shifts the whole wave up or down, and it becomes the new "middle line" that the amplitude is measured from. So here the amplitude is still just 1/5, but it's measured from y = 2 rather than from y = 0.

What "b" does — controls period (width/speed)

b controls how quickly the graph repeats. The relationship is:

Period formula Period = 360° ÷ b A bigger b squashes the graph horizontally (shorter period, faster repeating). A smaller b (like a fraction) stretches the graph out (longer period, slower repeating).

Example: for y = sin(2x), period = 360°/2 = 180°. The graph has been squashed horizontally by a factor of 2, so it now completes two full cycles in the space that used to fit just one (360°).

Example: for y = sin(½x), period = 360° ÷ ½ = 360 × 2 = 720°. The graph has been stretched out, so it now only completes half a cycle in 360° — you need a full 720° to see one complete wave.

Common mix-up Students often assume b makes the period bigger as b gets bigger — it's the opposite! A bigger b means the wave repeats faster, so the period is smaller. Always plug into 360°/b to check rather than guessing.
Practice Question

A wave y = a cos(bx) has amplitude 4 and completes exactly 3 full cycles between x = 0° and x = 360°. Find a and b.

Practice Question

The graph y = 2 + 3sin x is drawn. State (a) its amplitude, and (b) the equation of the horizontal line it oscillates around.

3. Solving Trig EquationsFinding every solution, not just the calculator's first guess

Why trig equations have multiple solutions

Here's the crucial thing that makes trig equations different from normal equations: because the graphs repeat and are symmetric, one equation can have several correct answers within a given range. Your calculator will only ever give you one of them (via the inverse function — sin⁻¹, cos⁻¹, tan⁻¹) — it's your job to use the shape of the graph to hunt down the rest.

Every question will give you an interval to search in, e.g. 0° ≤ x ≤ 360°. Any solutions outside that range don't count, even if they're mathematically valid.

Solving sin x = ...

Step 1: Use your calculator's inverse sin function to get the first solution.
Step 2: Sketch the sine graph over the given interval, and mark that first solution on it.
Step 3: Use the symmetry of the wave to spot the second solution.

Worked example: Solve sin x = 0.5 for 0° ≤ x ≤ 360°.

1 | y = sin x | ___ 0.5 | / | \ | / | \ 0 |__/______|______\_______ x |0 30° 180° 360° | ↑ | 180° - 30° = 150° | (by symmetry)

First solution: x = sin⁻¹(0.5) = 30°. Because sine is symmetric about x = 90° (the peak), the second solution is found by 180° − 30° = 150°. Both angles give the same sin value because they're mirror images of each other across the peak of the wave.

The sin rule If x is an acute solution to sin x = ..., then 180° − x is another solution to the same equation. Always check both solutions by substituting them back into sin(x) on your calculator — they should both give the same value.

Solving cos x = ...

The method is the same, but the symmetry rule is different because cos x is symmetric about x = 0° and x = 360° (not about 90°).

Worked example: Solve cos x = 0.5 for 0° ≤ x ≤ 360°.

1 | y = cos x |\ / 0.5 | \ 60° / | \ | / 0 |_____\___|__/____________ x |0 ↑ 180 ↑ 360° | 60° 360°-60°=300° | (by symmetry)

First solution: x = cos⁻¹(0.5) = 60°. By symmetry, the second solution is 360° − 60° = 300°.

The cos rule If x is a solution to cos x = ..., then 360° − x is another solution to the same equation.

Solving tan x = ...

Tan doesn't work by mirror symmetry — because it's not a wave, it doesn't have a peak to reflect around. Instead, you use its periodic nature: every branch is identical, just shifted along by 180°. So once you have one solution, you just keep adding (or subtracting) 180° to find the rest within your interval.

Worked example: Solve tan x = 1 for 0° ≤ x ≤ 360°.

| branch1 |branch2 | | /| /| /| 1 | / | / | / | | /45°+180° / | 0 |_/___|_/=225°___|_______ x | 45° 90 180 270 360

First solution: x = tan⁻¹(1) = 45°. Adding 180° (one full period): 45° + 180° = 225°. Both are valid solutions within 0°–360°.

The tan rule If x is a solution to tan x = ..., then x + 180° is another solution to the same equation.

Rearranging trig equations first

Equations aren't always handed to you neatly as "sin x = 0.5." Sometimes you'll need to rearrange first. For example, 2 sin x − 1 = 0 rearranges (add 1, then divide by 2) to sin x = ½ — then you solve exactly as normal.

What if the first calculator answer is negative?

Sometimes your calculator spits out a negative angle for the first solution — that's completely normal, it just means the "natural" first solution sits to the left of 0° on the graph. Don't panic: extend your sketch to the left of the y-axis to see it, then use symmetry/periodicity as usual to find the solutions that actually fall inside your given range.

Common mistake Giving only ONE answer when a question clearly has two (or more) in the range. Exam mark schemes almost always award marks for each valid solution separately — missing the second solution is one of the most common ways students lose easy marks on this topic. Always ask yourself: "does the range allow for another solution I haven't found yet?"
Practice Question

Solve cos x = 0.8 for 0° ≤ x ≤ 360°, giving your answers to 1 decimal place.

Practice Question

Solve 2tan x + 3 = 1 for 0° ≤ x ≤ 360°.

What to MemoriseYour quick-reference cheat sheet

  Graph basics

  • sin x: through (0,0), amplitude 1, period 360°
  • cos x: through (0,1), amplitude 1, period 360°
  • tan x: through (0,0), no amplitude, period 180°, asymptotes every 180° starting at 90°
  • cos x = sin x shifted 90° left

  Amplitude & period

  • Amplitude = ½ × (max − min)
  • Period = distance for one full repeat
  • y = a sin(bx): a = amplitude, b affects period
  • Period = 360° ÷ b

  Solving rules

  • sin: second solution = 180° − x
  • cos: second solution = 360° − x
  • tan: next solution = x + 180° (or −180°)
  • Always check answers by substituting back in

  Process for any equation

  • 1. Rearrange into sin x = k / cos x = k / tan x = k
  • 2. Find first solution using inverse function
  • 3. Sketch the graph over the given interval
  • 4. Use symmetry/periodicity to find ALL solutions in range
Concepts ChecklistTick off each idea once you're confident with it
Exam TipsWhat examiners actually look for — and where marks get lost
Use your GDC to check, not to guess Your graphic display calculator can plot and interpret trig graphs — use it to check your sketch looks right, but you still need to be able to reason through amplitude/period by hand, since not every exam board allows GDC use for every paper.
Don't stop at one solution The single biggest mark-loser on this topic is giving only the calculator's answer and forgetting to search for the second (or further) solutions using symmetry/periodicity. Always re-read the interval given in the question and ask "could there be more?"
Know your inverse function buttons Practice using sin⁻¹, cos⁻¹, and tan⁻¹ on your actual calculator before the exam — fumbling with the buttons under time pressure costs valuable minutes.
Round only at the very end If a question asks for answers to 1 decimal place, keep full accuracy through your working (don't round the first solution before finding the second) and only round your final answers.
a controls height, b controls width — don't swap them A classic trap question gives you a graph and asks you to state a and b. Always find the amplitude first (that's a), then use the period formula 360°/b to solve for b — don't try to read b directly off the graph.
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