Advanced Inorganic & Organic Chemistry Core Practicals
Revise Advanced Inorganic & Organic Chemistry Core Practicals for Chemistry (IAL) — revision notes and instant AI marking. Free to start.
Advanced Inorganic & Organic
Chemistry Core Practicals
The Big Idea: Five practicals, one skill underneath all of them — using colour changes, precipitates, and precise measurements to work out exactly how much of something is present, or exactly what something is, by controlling every variable so the only thing that changes is the chemistry you're trying to observe.
Summary — What This Chapter Covers
- Core Practical 13a: Redox titration between iron(II) and manganate(VII) — self-indicating, no indicator needed.
- Core Practical 13b: Redox titration between iodine and thiosulfate — uses starch as an indicator near the end point.
- Core Practical 12: Preparing a transition metal complex — tetraamminecopper(II) sulfate crystals — and calculating percentage yield.
- Core Practical 15: Qualitative analysis — identifying unknown positive ions (Group 2 metals, ammonium), negative ions (halides, hydroxide, carbonate, sulfate), and organic functional groups (alkenes, alcohols, carbonyls, carboxylic acids).
- Core Practical 16: Preparing aspirin from salicylic acid, then purifying it by recrystallisation and checking its purity with a melting point test.
Redox Titration — Iron(II) & Manganate(VII)
Think of a titration as a chemical "weighing scale." You know the exact concentration of one solution (the one in the burette), and you slowly add it to a known volume of the other solution until the reaction is exactly complete. The volume you needed tells you how much of the unknown substance was there.
In a redox titration, instead of an acid neutralising a base, you have an oxidising agent reacting with a reducing agent — electrons are being transferred from one species to the other. The clever part is that many transition metal ions change colour when they change oxidation state, so you often don't even need to add a separate indicator — the reaction indicates itself.
Why Sulfuric Acid, and Nothing Else?
In this titration, manganate(VII) ions (MnO₄⁻) are the oxidising agent — they get reduced to Mn²⁺. Iron(II) is the reducing agent — it gets oxidised to Fe³⁺. This reaction only works in acidic conditions, so excess acid is added to the iron(II) solution before you even start titrating.
But you can't just grab any acid off the shelf. The acid has one job: provide H⁺ ions, and stay completely out of the redox chemistry. Dilute sulfuric acid is the only one that does this cleanly:
| Acid | Why it's rejected |
|---|---|
| Hydrochloric acid | Chloride ions get oxidised to chlorine by the manganate(VII) — it reacts when it shouldn't. |
| Nitric acid | It's an oxidising agent itself — it could oxidise the iron(II) directly, ruining the titre. |
| Ethanoic acid | It's a weak acid — not enough H⁺ ions are released to keep the solution acidic enough. |
| Concentrated sulfuric acid | Concentrated (not dilute) sulfuric acid can act as an oxidising agent too. |
Spotting the End Point
Potassium manganate(VII) is intensely purple. As you drip it into the (acidified) iron(II) solution, it reacts instantly and is decolourised — the Mn²⁺ produced is such a pale pink that the solution just looks colourless. This continues until every Fe²⁺ ion has reacted. The very next drop of manganate(VII) has nothing left to react with, so it survives, and the whole flask turns a persistent pale pink. That's your end point.
Building and Balancing the Equation
You're given two half-equations and asked to combine them. The rule is always the same: multiply each half-equation so the number of electrons matches, then add them together and cancel the electrons.
Fe²⁺(aq) → Fe³⁺(aq) + e⁻ (× 5 to balance electrons)
Notice the mole ratio buried in that equation: 1 mole of MnO₄⁻ reacts with 5 moles of Fe²⁺. Every calculation in this practical hinges on that 1:5 ratio.
Worked Example — Analysing an Iron Tablet
Question: An iron tablet weighing 0.960 g was dissolved in dilute sulfuric acid. An average titre of 28.50 cm³ (approximated as 25.0 cm³ in the working below to match the source data) of 0.0180 mol dm⁻³ potassium manganate(VII) solution was needed to reach the end point. What is the percentage by mass of iron in the tablet?
Step 1 — moles of MnO₄⁻ used:
moles = (0.0180 × 25.0) / 1000 = 5.13 × 10⁻⁴ mol
Step 2 — use the 1:5 ratio to get moles of Fe²⁺:
moles of Fe²⁺ = 5 × 5.13 × 10⁻⁴ = 2.565 × 10⁻³ mol
Step 3 — convert moles to mass using Mᵣ(Fe) = 56.0:
mass of Fe = 56.0 × 2.565 × 10⁻³ = 0.14364 g
Step 4 — express as a percentage of the tablet's total mass:
% by mass = (0.14364 / 0.960) × 100 = 15.0%
Why must the iron(II) solution be acidified before the titration begins, rather than during it?
A student uses hydrochloric acid instead of sulfuric acid to acidify their iron(II) solution. Explain the error this introduces and predict the effect on the calculated iron content.
Redox Titration — Thiosulfate & Iodine
This is a two-stage idea, and it's easy to get lost if you only look at the final titration equation. Here's the full logic chain:
- You have an oxidising agent of unknown concentration (e.g. chlorate(I) ions in bleach).
- You react it with an excess of iodide ions — the oxidising agent converts iodide into iodine (I₂). The amount of iodine produced is directly linked to how much oxidising agent was present.
- You then titrate that iodine against a sodium thiosulfate solution of known concentration. The volume of thiosulfate needed tells you exactly how much iodine was made — and working backwards, how much oxidising agent you started with.
Reading the Colour Changes
Iodine solution starts off light brown/yellow. As thiosulfate is added from the burette, the iodine is steadily converted to colourless iodide ions, and the solution gets paler and paler. Once it fades to a pale straw colour, that's your cue to add starch indicator — not at the start, because starch forms such an intense blue-black complex with iodine that it would mask the gradual colour change and make it impossible to judge when you're getting close to the end point.
Worked Example — Chlorate(I) in Household Bleach
Setup: 10.0 cm³ of bleach was made up to 250.0 cm³. A 25.0 cm³ portion of this diluted solution had 10.0 cm³ of 1.0 mol dm⁻³ potassium iodide added, then was acidified with 1.0 mol dm⁻³ HCl:
This was titrated against 0.05 mol dm⁻³ sodium thiosulfate, average titre = 25.20 cm³:
Step 1 — moles of thiosulfate used:
(0.05 × 25.20) / 1000 = 1.26 × 10⁻³ mol
Step 2 — moles of I₂ (and therefore ClO⁻) in the 25.0 cm³ sample — the S₂O₃²⁻ : I₂ ratio
is 2 : 1, and the ClO⁻ : I₂ ratio is 1 : 1, so:
1.26 × 10⁻³ / 2 = 6.30 × 10⁻⁴ mol
Step 3 — scale up to the full 250.0 cm³:
6.30 × 10⁻⁴ × 10 = 6.30 × 10⁻³ mol of ClO⁻
Step 4 — scale back to the original 10.0 cm³ of undiluted bleach, then to 1 dm³:
10 cm³ bleach contains 6.30 × 10⁻³ mol ClO⁻ → 1.0 dm³ contains 0.630 mol ClO⁻
Answer: concentration of ClO⁻ in the bleach = 0.630 mol dm⁻³
2. Combine into the overall equation.
3. Calculate moles of the titrant (manganate/dichromate/thiosulfate) used.
4. Read off the mole ratio from the overall equation.
5. Calculate moles of the substance you're analysing, in the sample solution.
6. Scale up (or down) to the moles in the original solution, if it was diluted.
7. Convert to a final concentration or percentage as the question asks.
Why is starch added only once the solution has turned pale straw-coloured, rather than at the very start of the titration?
A student forgets to dilute their 10.0 cm³ bleach sample to 250.0 cm³ and instead titrates the iodine produced from the concentrated sample directly. What practical problem would they run into, and why does the dilution step matter for the maths?
Preparing a Transition Metal Complex
This practical makes crystals of tetraamminecopper(II) sulfate-1-water, Cu(NH₃)₄SO₄·H₂O, starting from ordinary copper(II) sulfate. The whole thing is really a story about solubility — you dissolve something, add a reagent to build a new, different compound in solution, and then force it back out as a solid by making the solvent "unfriendly" to it.
The Method, Step by Step
- Weigh 1.4–1.6 g of copper(II) sulfate accurately (weigh test tube empty, then with the solid — the difference is the mass).
- Dissolve it in 4 cm³ of water, warming gently in a water bath.
- In the fume cupboard, wearing gloves, add 2 cm³ of concentrated ammonia solution while stirring — the solution turns deep blue as the [Cu(NH₃)₄(H₂O)₂]²⁺ complex ion forms.
- Pour this into 6 cm³ of ethanol and cool in an ice bath — dark blue Cu(NH₃)₄SO₄·H₂O crystals precipitate out.
- Filter using a Büchner funnel (vacuum filtration — much faster than gravity filtration), wash with cold ethanol.
- Dry the crystals between filter paper, then weigh them.
Calculating Percentage Yield
This is a classic "actual vs. theoretical" calculation. You work out the maximum mass you could have made (assuming a perfect 1:1 reaction with no losses), then compare it to what you actually collected.
Worked Example
Reaction: CuSO₄·5H₂O + 4NH₃ → Cu(NH₃)₄SO₄·H₂O + 4H₂O
A student used 1.5 g of CuSO₄·5H₂O and obtained 1.2 g of dry product.
Step 1 — relative formula masses:
Mᵣ(CuSO₄·5H₂O) = 63.5 + 32.1 + (4×16.0) + 5×((2×1.0)+16.0) = 249.6
Mᵣ(Cu(NH₃)₄SO₄·H₂O) = 63.5 + 4×(14.0+3×1.0) + 32.1 + (4×16.0) + (2×1.0) + 16.0 = 245.6
Step 2 — moles of CuSO₄·5H₂O used:
1.5 / 249.6 = 0.00601 mol
Step 3 — theoretical moles of product (the equation shows a 1:1 molar ratio):
0.00601 mol of Cu(NH₃)₄SO₄·H₂O expected
Step 4 — theoretical mass:
0.00601 × 245.6 = 1.48 g
Step 5 — percentage yield:
(1.2 / 1.48) × 100 = 81%
Safety in This Practical
| Hazard | Why it matters |
|---|---|
| Concentrated ammonia | Corrosive and dangerous to the environment — must be used in the fume cupboard, wearing gloves. It also releases toxic ammonia gas. |
| Copper salts | Harmful and dangerous to the environment. |
| Ethanol | Flammable — keep away from naked flames. |
Explain, in terms of solubility, why cooling the mixture in an ice bath after adding ethanol improves the yield of crystals.
Suggest two reasons why a student's percentage yield in this experiment might be lower than 100%, other than incomplete drying.
Qualitative Analysis of Inorganic & Organic Unknowns
This practical is a toolkit of "detective tests." You're handed an unknown substance, and each test gives you a clue — a colour change, a precipitate, a smell, a gas — that lets you rule ions and functional groups in or out. The trick to mastering this section isn't memorising every single line; it's understanding why each reagent produces the result it does, so you can reconstruct the table under exam pressure even if your memory blanks.
Testing for Positive Ions: Group 2 Metals
Add sodium hydroxide (or ammonia solution, or sulfuric acid) dropwise, in excess, to a solution of the unknown metal ion, and watch for a precipitate.
| Reagent | Mg²⁺ | Ca²⁺ | Sr²⁺ | Ba²⁺ |
|---|---|---|---|---|
| Ammonia solution | White ppt — Mg(OH)₂ | No change | No change | No change |
| Excess NaOH | White ppt — Mg(OH)₂ | White ppt — Ca(OH)₂ | Slight white ppt — Sr(OH)₂ | No change |
| Excess H₂SO₄ | Colourless (no ppt) | Slight white ppt — CaSO₄ | White ppt — SrSO₄ | White ppt — BaSO₄ |
Testing for Ammonium Ions (NH₄⁺)
Add sodium hydroxide to the unknown solution, then gently warm it in a water bath. Ammonium ions react with hydroxide to release ammonia gas: NH₄⁺(aq) + OH⁻(aq) → NH₃(g) + H₂O(l). Hold a piece of damp red litmus paper near (not in) the mouth of the tube using tongs.
Testing for Negative Ions
Halide Ions (Cl⁻, Br⁻, I⁻)
Add dilute nitric acid (to remove interference from other ions like carbonate), then add silver nitrate solution.
| Halide present | Precipitate colour | Formula | Behaviour with ammonia |
|---|---|---|---|
| Chloride, Cl⁻ | White | AgCl | Dissolves in dilute ammonia |
| Bromide, Br⁻ | Cream | AgBr | Dissolves only in concentrated ammonia |
| Iodide, I⁻ | Yellow | AgI | Does not dissolve, even in concentrated ammonia |
Hydroxide Ions (OH⁻)
Test the pH directly with red litmus paper or universal indicator. A positive result: red litmus turns blue, or the universal indicator paper reads clearly alkaline.
Carbonate Ions (CO₃²⁻)
Add dilute hydrochloric acid, then immediately attach a bung and delivery tube leading into a second test tube containing limewater (calcium hydroxide solution).
Sulfate Ions (SO₄²⁻)
Acidify the sample with dilute hydrochloric acid first, then add a few drops of aqueous barium chloride.
Testing for Organic Functional Groups
Alkenes / Unsaturation — Bromine Water Test
Shake the unknown compound with orange/yellow bromine water. If a carbon–carbon double bond is present, an addition reaction occurs and the bromine is used up.
Alcohols — PCl₅ Test
Add solid phosphorus(V) chloride. If an −OH group is present, a vigorous reaction occurs at room temperature, with no heating needed.
Distinguishing 1° / 2° Alcohols from Tertiary Alcohols — Oxidation Test
Warm the unknown with acidified potassium dichromate(VI), or acidified potassium manganate(VII).
| Alcohol type | Behaviour |
|---|---|
| Primary / secondary | Gets oxidised (to an aldehyde/ketone). Dichromate(VI): orange → green. Manganate(VII): purple → colourless. |
| Tertiary | Cannot be oxidised this way — no colour change at all. |
Carbonyls (General) — 2,4-DNPH Test
2,4-dinitrophenylhydrazine (2,4-DNPH) undergoes a condensation reaction with the carbonyl group (C=O) in both aldehydes and ketones.
Distinguishing Aldehydes from Ketones
Both Tollens' reagent and Fehling's solution rely on the same underlying idea: aldehydes can be oxidised further (to a carboxylic acid); ketones cannot.
| Reagent | With an aldehyde | With a ketone |
|---|---|---|
| Tollens' reagent (ammoniacal AgNO₃) | Silver mirror forms — Ag⁺ is reduced to Ag metal as the aldehyde is oxidised. | No reaction — no silver mirror. |
| Fehling's/Benedict's solution | Brick-red precipitate of Cu₂O forms — Cu²⁺ reduced to Cu⁺. | No reaction — stays clear blue. |
Carboxylic Acids
Add solid sodium carbonate, or aqueous sodium hydrogen carbonate.
A student adds excess sodium hydroxide to an unknown Group 2 metal chloride solution and sees no precipitate at all. They then test with excess sulfuric acid and see a dense white precipitate immediately. Identify the metal ion and justify your answer.
An unknown liquid gives a positive result with 2,4-DNPH (orange precipitate) but no silver mirror with Tollens' reagent, and no colour change when warmed with acidified potassium dichromate(VI). What type of compound is it, and how do you know?
Aspirin Preparation
This practical brings together several separate skills you've built up across the chapter: accurate measurement, controlled heating, purification by recrystallisation, and using a melting point to check purity. It's really two experiments glued together — first you make the aspirin, then you purify and verify it.
Stage 1 — Synthesis
- Add 6.0 g of salicylic acid to a conical flask with 10 cm³ of ethanoic anhydride and 5 drops of concentrated sulfuric acid (a catalyst).
- Swirl and hold in a warm water bath at around 60°C for about 20 minutes.
- Cool the flask, then pour the contents into 75 cm³ of cold water — the aspirin crystallises out.
- Recover the crude aspirin by Büchner (vacuum) filtration, and leave to dry.
Stage 2 — Recrystallisation (Purification)
The crude aspirin you've collected is impure — it contains left-over reactants and by-products. Recrystallisation is the standard technique for purifying an organic solid, and the logic is elegant:
- Dissolve the impure solid in the minimum volume of hot solvent (here, ethanol) needed to fully dissolve it.
- If any insoluble impurities remain, filter the hot solution (a "hot filtration").
- Let the solution cool slowly to room temperature — the desired product crystallises out, but the impurities (present in much smaller amounts) stay dissolved in the solvent.
- Filter again (typically Büchner filtration, since it's faster — filtration under reduced pressure) to collect the pure crystals.
- Wash with a small amount of fresh, cold solvent to remove any remaining surface impurities, then dry.
Stage 3 — Melting Point Analysis
The melting point of a solid is a fingerprint for both its identity and its purity. Pure aspirin melts sharply at 135°C.
| Observation | What it tells you |
|---|---|
| Melting point matches the literature value closely | Product is likely to be pure aspirin. |
| Melting point is lower than the literature value | Impurities are present — impurities characteristically lower a substance's melting point. |
| Melting occurs over a wide temperature range | The sample is impure — pure substances melt sharply over a very narrow range; impure ones melt gradually over a broad range. |
Practical Skills for a Good Melting Point Test
- The sample must be completely dry and finely powdered — crush it with the back of a spatula on filter paper or a white tile to absorb any remaining moisture.
- Do a quick first run to find the approximate melting range, heating fairly fast.
- Repeat with a much slower heating rate for an accurate reading — heating too fast means the thermometer reading lags behind the true temperature of the sample, giving you an inaccurately high value.
- Take repeat readings (three is standard) and quote the result as a range, ideally referenced against a data book value.
A student measures the melting point of their recrystallised aspirin as 128–133°C, compared to the literature value of 135°C. What does this tell you about the purity of their product, and why does an impure solid melt over a range rather than at one exact temperature?
Explain why the crystals are washed with cold ethanol (rather than hot ethanol, or water) as the final step of recrystallisation.
What to Memorise
Manganate(VII) titration equation
MnO₄⁻ + 8H⁺ + 5Fe²⁺ → Mn²⁺ + 4H₂O + 5Fe³⁺ (mole ratio MnO₄⁻:Fe²⁺ = 1:5)
Thiosulfate–iodine equation
2S₂O₃²⁻ + I₂ → 2I⁻ + S₄O₆²⁻ (mole ratio S₂O₃²⁻:I₂ = 2:1)
Why sulfuric acid, not others
HCl gets oxidised; HNO₃ is itself an oxidiser; ethanoic acid is too weak; conc. H₂SO₄ can oxidise too.
Halide precipitate colours
Cl⁻ → white (AgCl); Br⁻ → cream (AgBr); I⁻ → yellow (AgI). Test with AgNO₃ after acidifying with HNO₃.
Sulfate test
Acidify with HCl first (removes carbonate), then add BaCl₂ → white BaSO₄ precipitate.
Carbonate test
Add dilute HCl → CO₂ gas evolved → turns limewater milky/cloudy.
Alkene test
Shake with bromine water → orange decolourises if C=C double bond present.
Alcohol tests
PCl₅ → steamy HCl fumes confirms −OH. Dichromate(VI)/manganate(VII): 1°/2° alcohols oxidised (colour change); 3° alcohols unaffected.
Aldehyde vs ketone
Tollens': aldehyde gives silver mirror, ketone gives none. Fehling's: aldehyde gives brick-red ppt, ketone gives none.
Carboxylic acid test
Add Na₂CO₃ or NaHCO₃ → effervescence (CO₂ gas evolved).
Percentage yield formula
% yield = (actual mass obtained ÷ theoretical mass) × 100
Recrystallisation core principle
Dissolve in minimum hot solvent → hot filter if needed → cool slowly to crystallise → filter → wash with cold solvent → dry.
Concepts Checklist
Exam Tips — Common Mistakes & Mark-Scheme Traps
- "Explain why [acid X] is unsuitable for this titration" — always link back to redox interference, not just general reactivity.
- Full titration calculations requiring the 7-step method (moles → ratio → scale-up → final answer).
- "Identify the ion(s) present" from a table of test results — work through each test's logic, don't guess.
- "Suggest why the percentage yield is greater than 100%" — always link to incomplete drying/impure product.
- "Describe how you would purify this compound and check its purity" — full method plus melting point interpretation.
Revision guide generated from Edexcel International A Level (IAL) Chemistry — Advanced Inorganic & Organic Chemistry Core Practicals. Study smart, not just hard. 💜
- Redox Titration — Iron(II) & Manganate(VII)
- Redox Titration — Thiosulfate & Iodine
- Qualitative Analysis of Inorganic & Organic Unknowns
- Exam Tips — Common Mistakes & Mark-Scheme Traps
Read the full Advanced Inorganic & Organic Chemistry Core Practicals notes free
That's the preview — create a free account to read the rest, plus flashcards and practice questions with instant AI marking. No credit card.
Unlock the full notes free →