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Organic Chemistry: Nitrogen Compounds

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  Edexcel IAL Chemistry · Organic Chemistry

Nitrogen Compounds: Amines, Amides & Amino Acids

🧠 The Big Idea: Nitrogen's lone pair of electrons is the key to everything in this chapter — it makes amines basic (they grab protons), it makes nitrogen a great nucleophile (it attacks electron-poor carbons to build amides and bigger amines), and when amino acids use both their amine AND acid groups to link up, they build the proteins your body is made of.

📋 Summary — What This Chapter Covers

  • Amines = ammonia (NH₃) with one or more H's swapped for alkyl/aryl groups. Classified as primary, secondary, tertiary based on how many H's on the nitrogen have been replaced.
  • Amine basicity depends on how available the nitrogen's lone pair is — alkyl groups push electron density on (more basic); benzene rings pull it into the ring via delocalisation (less basic).
  • Amines react with acids (→ salts), acyl chlorides (→ amides), halogenoalkanes (→ bigger amines, eventually quaternary salts), and Cu²⁺ ions (→ coloured complexes, like ammonia).
  • Primary amines are made by reacting halogenoalkanes with excess ammonia, or by reducing nitriles (LiAlH₄ or H₂/Ni catalyst).
  • Phenylamine is made from nitrobenzene in a 2-stage reduction: Sn/HCl reflux → phenylammonium ion, then NaOH → phenylamine. It's a weaker base than ammonia because the lone pair delocalises into the ring.
  • Amides (–CONR₂) form from acyl chlorides + ammonia/amines via condensation (addition-elimination), releasing HCl.
  • Condensation polymers — polyesters (ester links, from diols + diacids) and polyamides (amide links, from diamines + diacids) — form by repeatedly eliminating small molecules (usually H₂O or HCl).
  • Amino acids are amphoteric (both acidic –COOH and basic –NH₂). In solution they form zwitterions — one molecule, two opposite charges.
  • The isoelectric point is the pH where the amino acid is a perfectly neutral zwitterion (equal + and − charge).
  • Amino acids link via peptide bonds (a type of amide bond) to form dipeptides, tripeptides, and eventually polypeptides/proteins.

1. Amines, Amides & Amino Acids — The Family

Think of ammonia (NH₃) as the "parent" molecule for this whole chapter. Everything here is basically ammonia with some of its hydrogens swapped out for carbon-based groups:

H R R R | | | | H-N-H H-N-H R-N-H R-N-R | | | | H H R R AMMONIA PRIMARY SECONDARY TERTIARY AMINE AMINE AMINE (0 H's (1 H (2 H's (3 H's replaced) replaced) replaced) replaced)
⚠️ Classic Trap
This classification is NOT the same as primary/secondary/tertiary alcohols or haloalkanes! For alcohols and haloalkanes, you look at the carbon the OH/halogen is attached to. For amines, you look at how many hydrogens on the nitrogen have been replaced. A carbon attached to three other carbons can still be part of a "primary" amine if only one H on the N is swapped.

Aliphatic vs Aromatic

If the R group is an alkyl chain (methyl, ethyl...) it's an aliphatic amine. If the R group is a benzene ring (phenyl), it's an aromatic amine. This distinction matters hugely for basicity — more on that in Topic 2.

Naming Amines

StructureCommon nameIUPAC systematic name
CH₃NH₂methylamineaminomethane
C₂H₅NH₂ethylamineaminoethane
(CH₃)₂NHdimethylamineN-methylaminomethane
(CH₃)₃NtrimethylamineN,N-dimethylaminomethane
C₆H₅NH₂phenylamineaminobenzene

Notice the pattern for secondary/tertiary amines: extra alkyl groups on the nitrogen get an N- prefix, because they're on the nitrogen, not on the main carbon chain.

Amides — the other nitrogen family

Amides have the general structure RCONR'R'' — a carbonyl group (C=O) directly bonded to a nitrogen. They're classified the same logical way as amines (by counting carbons bonded to the amide nitrogen):

  • Primary amide — one carbon bonded to N (the carbonyl carbon). e.g. CH₃CONH₂ = ethanamide.
  • Secondary amide — two carbons bonded to N (carbonyl + one alkyl). Name the alkyl group with an N- prefix. e.g. CH₃CONH(C₃H₇) = N-propylethanamide.
  • Tertiary amide — three carbons bonded to N (carbonyl + two alkyls, listed alphabetically). e.g. CH₃CON(CH₃)(C₃H₇) = N-methyl-N-propylethanamide.

Amino acids — the building blocks of life

Amino acids carry two functional groups on the same molecule: a basic amino group (–NH₂) and an acidic carboxylic acid group (–COOH). Because they're both acidic and basic at once, they're called amphoteric.

The 20 naturally occurring amino acids are all "2-aminocarboxylic acids" — meaning the –NH₂ is bonded to the carbon right next to the –COOH. General formula: RCH(NH₂)COOH. The "R" group is different for each of the 20 amino acids, and can be acidic, basic, or neutral — this is what gives each amino acid its unique personality and lets proteins fold into complex 3D shapes.

Practice Question 1.1
Classify CH₃CH₂NHCH₃ as a primary, secondary or tertiary amine, and give its systematic name.
Practice Question 1.2
Draw and name the amide formed from propanoyl chloride and dimethylamine.

2. Primary Aliphatic Amines — Reactions

Solubility & Reaction with Water

Small amines dissolve well in water because they form hydrogen bonds with water molecules (the N–H bonds and the lone pair on N both participate). As the hydrocarbon "tail" gets longer, solubility drops — the molecule becomes more like a nonpolar hydrocarbon and less water-loving. Phenylamine, with its bulky nonpolar benzene ring, is only slightly soluble.

Amines are weak bases, so they react slightly with water to set up an equilibrium:

Reaction with water
CH₃NH₂ + H₂O ⇌ CH₃NH₃⁺ + OH⁻
This is why aqueous amine solutions are slightly alkaline — it's the same idea as ammonia dissolving in water to make a weakly alkaline solution.

Amine Basicity — the heart of this topic

The nitrogen atom in every amine (and in ammonia) has a lone pair of electrons. That lone pair can grab hold of a proton (H⁺) and form a dative covalent bond. This is exactly what it means to be a Brønsted-Lowry base — a base is a proton acceptor.

AMMONIA: NH₃ + H⁺ → NH₄⁺ PRIMARY AMINE: R-NH₂ + H⁺ → R-NH₃⁺ SECONDARY AMINE: R₂NH + H⁺ → R₂NH₂⁺

The stronger the base, the more "available" that lone pair is — i.e. the more willing it is to grab a proton. Two effects control this availability:

Positive Inductive Effect (makes bases STRONGER)
Alkyl groups (like CH₃-, C₂H₅-) are electron-donating. They push electron density towards the nitrogen, making its lone pair more negative and more eager to grab a proton. More alkyl groups on nitrogen = stronger base.
Delocalisation (makes bases WEAKER)
In aromatic amines like phenylamine, the nitrogen's lone pair gets pulled into the benzene ring's π system (delocalised electron cloud). This spreads the lone pair out and makes it much less available to accept a proton — so aromatic amines are weaker bases than you'd expect.
BASE STRENGTH RANKING (strongest → weakest): secondary amine > primary aliphatic amine > ammonia > phenylamine (CH₃CH₂)₂NH CH₃CH₂NH₂ NH₃ C₆H₅NH₂ more alkyl groups pushing electron density onto N →→→→ lone pair delocalised into ring

Why is a secondary amine a stronger base than a primary amine? Because it has two alkyl groups pushing electron density onto the nitrogen instead of one, so the inductive effect is bigger.

Why is phenylamine a weaker base than ammonia? Ammonia has no delocalisation to worry about at all — nothing is pulling its lone pair away. Phenylamine's lone pair is constantly being "borrowed" by the ring, so it's much less available.

Rule to remember
Electron-donating groups on N → stronger base. Delocalisation of N's lone pair → weaker base.

Reactions with Acids

Because amines are basic, they react with strong acids (like HCl) to form ionic ammonium salts:

Salt formation
CH₃NH₂ (aq) + HCl (aq) → CH₃NH₃⁺Cl⁻ (aq)
Adding NaOH to the salt reverses this reaction, regenerating the free amine. These salts are ionic, so they crystallise as solids when water evaporates, and — importantly — they're much more water-soluble than the parent amine. This is why phenylamine (barely soluble) becomes very soluble once turned into phenylammonium chloride.

Reaction with Ethanoyl Chloride (→ Amides)

This is an addition-elimination reaction: the amine's nitrogen attacks the electron-poor carbonyl carbon of the acyl chloride, and HCl is eliminated. You don't need the mechanism, just the outcome — a new amide functional group is formed.

Example
CH₃COCl + CH₃CH₂CH₂CH₂NH₂ → CH₃CONHCH₂CH₂CH₂CH₃ + HCl

Reaction with Halogenoalkanes — the chain reaction you must not underestimate

This is a nucleophilic substitution: the electron-rich N attacks the electron-poor carbon of the halogenoalkane. But here's the trick — the product still has a nitrogen lone pair, so it can react again. And again. This keeps going until all four positions around nitrogen are filled with carbon groups, forming a quaternary ammonium salt.

STEP 1: R'NH₂ + R''X → R'NHR'' + HX (primary → secondary amine) STEP 2: R'NHR'' + R''X → R'NR''₂ + HX (secondary → tertiary amine) STEP 3: R'NR''₂ + R''X → R'NR''₃⁺ X⁻ (tertiary amine → QUATERNARY AMMONIUM SALT — no HCl formed this time, because there's no N-H left to lose!)
Why no HCl in the last step?
Forming HCl requires an N–H bond to break. A tertiary amine has zero N–H bonds left — all three positions already have carbon groups. So the fourth substitution just forms an ionic salt directly: a nitrogen with 4 bonds to carbon (positively charged) paired with a Cl⁻ ion.

Reactions with Copper(II) Ions

Just like ammonia, amines can act as ligands and donate their lone pair to Cu²⁺. With excess amine you get the classic two-stage colour change you may have seen with ammonia:

  • Small amount of amine: pale blue precipitate of Cu(OH)₂ forms.
  • Excess amine: precipitate dissolves to give a deep blue solution (a Cu²⁺-amine complex).
Practice Question 2.1
Explain why ethylamine is a stronger base than phenylamine, referring to the nitrogen's lone pair.
Practice Question 2.2
Butylamine is reacted with excess chloroethane. Describe what happens, and name the final ionic product formed.

3. Preparing Primary Amines

Method 1: Halogenoalkane + Ammonia

This is a nucleophilic substitution — ammonia's lone pair attacks the electron-poor carbon of the halogenoalkane, kicking out the halogen. To favour a primary amine (and stop the chain reaction described in Topic 2 running away to quaternary salts), you use a large excess of hot, ethanolic ammonia, under pressure.

Conditions
Halogenoalkane + excess NH₃ (ethanol, heat, pressure) → primary amine + NH₄X
Excess ammonia means there's always far more NH₃ around than partially-substituted amine, so statistically the halogenoalkane is much more likely to hit an ammonia molecule than to hit the primary amine product and react further.

Method 2: Reduction of Nitriles

Nitriles (–C≡N) can be reduced to primary amines (–CH₂NH₂). Two ways to do this:

  • LiAlH₄ in dry ether — a strong reducing agent, adds 4[H] across the triple bond.
  • H₂ gas + nickel catalyst — catalytic hydrogenation, adds 2H₂.
Example
CH₃CN + 4[H] → CH₃CH₂NH₂ (using LiAlH₄)
CH₃CN + 2H₂ → CH₃CH₂NH₂ (using Ni catalyst)
Handy bonus
This nitrile route is a great way to add an extra carbon to a chain in a synthesis pathway, since going from a halogenoalkane → nitrile (via CN⁻) → amine bumps the carbon count up by one, unlike the ammonia route which keeps the same number of carbons.
Practice Question 3.1
Suggest why using excess ammonia (rather than a small amount) is essential for making a good yield of primary amine from a halogenoalkane.

4. Aromatic Amines — Making & Reacting Phenylamine

Making Phenylamine from Nitrobenzene (3 stages)

NO₂ NH₃⁺ NH₂ | Sn/HCl | NaOH(aq) | [benzene] --reflux--> [benzene] ----------> [benzene] NITROBENZENE PHENYLAMMONIUM PHENYLAMINE ION

Stage 1 — Reduction

Nitrobenzene is refluxed with tin (Sn) and concentrated HCl. Tin + HCl acts as the reducing agent — tin is oxidised (to a mix of Sn²⁺ and Sn⁴⁺) while nitrobenzene is reduced. But because the conditions are acidic, the product formed isn't phenylamine directly — it's the phenylammonium ion, C₆H₅NH₃⁺ (the amine gets instantly protonated by all that acid around).

Stage 2 — Formation of Phenylamine

Excess NaOH is added to deprotonate the phenylammonium ion, releasing the free phenylamine.

Stage 3 — Purification

The crude phenylamine is purified by steam distillation, then NaCl is added ("salting out") and the mixture is extracted with ether in a separating funnel. The ether layer (containing phenylamine) is distilled off; pure phenylamine boils at 180–185°C.

Exam favourite question
"Why is phenylamine formed as the phenylammonium ion in Stage 1, not as free phenylamine?" — Answer: because the reaction is carried out under strongly acidic conditions (concentrated HCl), and phenylamine is basic, so it immediately gets protonated by the excess H⁺ present.

Azo Compounds (Diazonium Chemistry)

Azo compounds contain an R₁–N=N–R₂ group, and are famous as brightly-coloured dyes. They're made through a 3-step process starting from phenylamine.

StepWhat happensConditions
1. Make nitrous acidNaNO₂ + HCl → HNO₂ + NaCl (nitrous acid is unstable, made fresh in situ)N/A
2. DiazotisationPhenylamine + HNO₂ + HCl → benzenediazonium chloride + 2H₂OBelow 10°C (use ice) — the diazonium ion decomposes above this!
3. Coupling reactionDiazonium ion + phenol → azo dye + HClAlkaline conditions (to deprotonate the phenol)
⚠️ Temperature control is critical
Diazotisation (Step 2) MUST be kept below 10°C using an ice bath. Above this temperature, the diazonium ion thermally decomposes back into benzene and nitrogen gas (N₂) instead of surviving to react in the coupling step. This is one of the most commonly tested practical details in this topic.

The diazonium ion acts as an electrophile and substitutes into the phenol ring at the 4th position (para to the OH group). The resulting azo compound is very stable because the delocalised π electrons of both benzene rings extend right through the –N=N– bridge — this extended delocalisation is also what gives azo dyes their vivid, visible colours (they absorb specific wavelengths of visible light).

Practice Question 4.1
Explain, using ideas about temperature and stability, why the diazotisation reaction must be carried out below 10°C.

5. Amide Formation

Amides form via a condensation reaction between an acyl chloride and ammonia (or an amine). "Condensation" means two molecules join together while a small molecule is kicked out — here, that small molecule is HCl.

Why does this reaction happen? (the mechanism logic)

The chlorine atom in an acyl chloride is highly electronegative, pulling electron density away from the carbonyl carbon. This makes that carbon electron-deficient and vulnerable to attack by any nucleophile. Ammonia and amines have a nitrogen lone pair that's a perfect nucleophile — it attacks the carbonyl carbon, the C–Cl bond breaks, and an amide is formed.

General reaction
Acyl chloride + NH₃/amine → amide + HCl
Nucleophile usedProduct typeExample
Ammonia (NH₃)Non-substituted (primary) amideCH₃CH₂COCl + NH₃ → CH₃CH₂CONH₂ + HCl
Primary amine (RNH₂)Substituted (secondary) amideCH₃CH₂COCl + CH₃NH₂ → CH₃CH₂CONHCH₃ + HCl
Secondary amine (R₂NH)Substituted (tertiary) amideCH₃CH₂COCl + (CH₃)₂NH → CH₃CH₂CON(CH₃)₂ + HCl
Don't forget the side reaction!
When ammonia is the nucleophile, the HCl by-product will react with any excess ammonia present (NH₃ + HCl → NH₄Cl). So the overall equation you often need to write is:

CH₃CH₂COCl + 2NH₃ → CH₃CH₂CONH₂ + NH₄Cl

Two moles of ammonia are needed — one to form the amide, one to mop up the HCl.
Practice Question 5.1
Write the equation for the reaction between ethanoyl chloride and excess ammonia, including any side reaction, and name the organic product.

6. Condensation & Addition Polymerisation

You already know addition polymerisation (alkenes joining via their C=C bonds, e.g. polyethene). This chapter introduces condensation polymerisation — a completely different mechanism where monomers join together while continuously eliminating small molecules (usually H₂O, sometimes HCl).

The key identifier
Condensation polymers are linked by ESTER bonds or AMIDE bonds (not by a simple C-C backbone)

Polyesters

Formed from a diol (2 × –OH groups) reacting with a dicarboxylic acid (2 × –COOH groups). Each ester link forms by losing one H₂O molecule. Because both monomers have two reactive ends, the chain just keeps growing.

HO-CH₂CH₂-OH + HOOC-⬡-COOH -H₂O→ -O-CH₂CH₂-O-CO-⬡-CO- ethane-1,2-diol benzene-1,4- [this repeats "n" times] dicarboxylic acid ↓ Poly(ethylene terephthalate) = PET (also known as Terylene / Dacron)

Alternative route: a single monomer called a hydroxycarboxylic acid — which has BOTH an –OH and a –COOH on the same molecule — can self-condense to form a polyester on its own, without needing a second monomer type. Each molecule's –OH end reacts with the next molecule's –COOH end.

Polyamides

Formed from a diamine (2 × –NH₂ groups) reacting with a dicarboxylic acid (2 × –COOH groups), losing H₂O at each amide link. Alternatively, a more reactive (but pricier) dioyl dichloride (2 × –COCl groups) can replace the diacid — in that case HCl is eliminated instead of H₂O.

PolymerMonomersLink type
Nylon-6,61,6-diaminohexane + hexane-1,6-dioic acidAmide
Kevlar1,4-diaminobenzene + benzene-1,4-dicarboxylic acidAmide
Terylene (PET)Ethane-1,2-diol + benzene-1,4-dicarboxylic acidEster
Why is Kevlar so strong?
Kevlar's polymer chains line up neatly side by side and form many hydrogen bonds between adjacent chains (thanks to the amide N-H and C=O groups). This dense hydrogen-bonding network is what makes it strong, flexible AND fire-resistant enough for bullet-proof vests.

Physical Properties of Polyamides

  • Semi-crystalline, tough, with good thermal & chemical resistance.
  • Absorb moisture from surroundings (until equilibrium) — water content increases flexibility & impact resistance but decreases strength & stiffness.
  • Used as fibres (clothing, Kevlar) and as films (cling film — tough, gas-impermeable, and heat-resistant, so also used for "boil-in-the-bag" foods).

Poly(ethenol) — a special case

Poly(ethenol) (poly(vinyl alcohol)) can't be made by directly polymerising its monomer "ethenol" — that molecule is actually unstable (it spontaneously rearranges to ethanal!). Instead, it's made indirectly in two stages:

STAGE 1: Polymerise ethenyl ethanoate (addition polymerisation) → poly(ethenyl ethanoate) STAGE 2: React with methanol (ESTER EXCHANGE) poly(ethenyl ethanoate) + CH₃OH → poly(ethenol) + CH₃COOCH₃

The amount of ester exchange is controlled by temperature — this controls how many –O-CO-CH₃ groups get swapped for –OH groups, which in turn controls the polymer's water solubility (ranging from insoluble → soluble in hot water → soluble in cold water).

Real-world use
Poly(ethenol)'s water solubility makes it perfect for dissolvable hospital laundry bags (dirty, potentially infectious linens go straight in the washing machine without staff touching them) and for the outer casing of liquid-detergent capsules/pods.
Practice Question 6.1
A polymer's repeating unit contains the group -NH-(CH₂)₆-NH-CO-(CH₂)₄-CO-. Identify the two monomers used to make it and state the type of polymerisation.

7. Characteristic Behaviour of Amino Acids

Zwitterions — the key concept of this topic

An amino acid has an acidic –COOH group and a basic –NH₂ group on the same molecule. Rather than sitting there neutral, these groups react with each other: the –COOH donates a proton to the –NH₂. The result is a single molecule with a positive charge in one place and a negative charge in another — this is called a zwitterion.

NH₂ ⁺NH₃ | | R --- C --- H ------> R --- C --- H | | COOH COO⁻ "normal" structure ZWITTERION (rarely how it actually (how the molecule ACTUALLY exists, exists in reality) even in the solid state!)
Zwitterion definition
An ion carrying both a positive charge (-NH₃⁺) and a negative charge (-COO⁻) on the same molecule — overall neutral
Because zwitterions have full-blown ionic charges (not just polar bonds), there are strong ionic-style intermolecular forces between amino acid molecules. This is why amino acids are crystalline solids with surprisingly high melting points for their size, and why they're soluble in water.

The Isoelectric Point

A solution of amino acid in water naturally sits mostly as the neutral zwitterion. But this zwitterion is sensitive to pH — it acts like a buffer, resisting small changes in pH:

ConditionWhat happens to the zwitterionResult
Acid added (pH lowered)The –COO⁻ part accepts an H⁺, reforming –COOHMolecule becomes a net positive ion
Base added (pH raised)The –NH₃⁺ part donates an H⁺, reforming –NH₂Molecule becomes a net negative ion
LOW pH ISOELECTRIC POINT HIGH pH ⁺NH₃ ⁺NH₃ NH₂ | -H⁺ | -OH⁻ | R-C-H <==========> R-C-H <==========> R-C-H | +H⁺ | +OH⁻ | COOH COO⁻ COO⁻ POSITIVE ION NEUTRAL ZWITTERION NEGATIVE ION
Isoelectric point definition
The pH at which the amino acid exists ENTIRELY as the neutral zwitterion (equal + and − charge, net zero)

Individual Reactions of Each Group

Even though amino acids naturally form zwitterions, they still undergo the "normal" reactions of amine groups and carboxylic acid groups separately when pushed with strong reagents:

Amine group + acid (salt formation)
H₂NCHRCOOH + HCl ⇌ H₃N⁺CHRCOOH + Cl⁻
Carboxylic acid group + alkali (salt formation)
H₂NCHRCOOH + NaOH ⇌ H₂NCHRCOO⁻Na⁺ + H₂O
Esterification (acidic conditions, so the amine gets protonated too!)
H₂NCHRCOOH + C₂H₅OH + H⁺ ⇌ H₃N⁺CHRCOOC₂H₅ + H₂O

Optical Activity

Almost every 2-amino acid has a chiral centre (the carbon bonded to –NH₂, –COOH, –H, and the R group — four different groups). This makes them optically active, meaning solutions rotate plane-polarised light either clockwise (dextrorotatory, +) or anticlockwise (laevorotatory, −).

The one exception
Glycine (R = H) is the only naturally occurring amino acid that is NOT optically active — its central carbon has TWO identical hydrogen substituents, so it isn't a true chiral centre (four different groups aren't all present).

If you synthesise an amino acid in a lab (rather than getting it from a living organism), you get a racemic mixture — a 50:50 mix of both mirror-image forms, which has no overall optical activity because the rotations cancel out.

Peptide Bonds — Building Proteins

The –COOH of one amino acid can condense with the –NH₂ of another, forming an amide bond (here specifically called a peptide bond or peptide link) and releasing H₂O.

Amino acid 1 Amino acid 2 H₂N-CHR-COOH + H₂N-CHR'-COOH -H₂O→ H₂N-CHR-CO-NH-CHR'-COOH ↑ peptide bond (an amide bond between 2 amino acids) This is now a DIPEPTIDE

The dipeptide still has a free –NH₂ at one end and a free –COOH at the other, so it can react again with another amino acid → tripeptide. Keep going with many amino acids → polypeptide (a protein).

Practice Question 7.1
Explain why glycine (H₂NCH₂COOH) does not exhibit optical activity, while alanine (H₂NCH(CH₃)COOH) does.
Practice Question 7.2
A solution of an amino acid is at a pH well below its isoelectric point. Describe the charge on the amino acid and explain, using an equation, how it got there.

🧠 What to Memorise

Amine classification (primary/secondary/tertiary)
Based on number of H's replaced ON THE NITROGEN — not on the carbon (unlike alcohols/haloalkanes).
Amine basicity order
secondary amine > primary aliphatic amine > ammonia > phenylamine (aromatic amine). Alkyl groups increase basicity (positive inductive effect); aromatic rings decrease it (delocalisation of the lone pair).
Amine + acyl chloride → amide + HCl
Condensation/addition-elimination reaction. New C(=O)-N bond formed.
Amine + halogenoalkane chain reaction
Primary → secondary → tertiary amine → quaternary ammonium salt (no HCl on the last step — no N-H left to lose!).
Making primary amines
(1) Halogenoalkane + EXCESS hot ethanolic NH₃ under pressure. (2) Reduction of nitriles with LiAlH₄/dry ether OR H₂/Ni catalyst.
Phenylamine synthesis (3 stages)
1) Nitrobenzene + Sn/conc. HCl, reflux → phenylammonium ion. 2) + excess NaOH → phenylamine. 3) Purify by steam distillation + ether extraction.
Diazotisation conditions
Phenylamine + NaNO₂/HCl (makes HNO₂ in situ) BELOW 10°C → benzenediazonium chloride. Above 10°C it decomposes to N₂ + phenol.
Azo coupling
Diazonium ion + phenol in ALKALINE conditions → azo dye (R-N=N-R') + HCl. Very stable due to extended delocalisation across both rings.
Polyester vs Polyamide
Polyester: diol + diacid, linked by ESTER bonds, eliminate H₂O. Polyamide: diamine + diacid (or dioyl dichloride), linked by AMIDE bonds, eliminate H₂O (or HCl with the dichloride).
Zwitterion
A single molecule with both a positive charge (-NH₃⁺) and negative charge (-COO⁻). This is how amino acids actually exist, even as solids.
Isoelectric point
The specific pH at which an amino acid exists purely as the neutral zwitterion (net charge = 0).
Peptide bond
An amide bond formed between the -COOH of one amino acid and the -NH₂ of another, releasing H₂O. Links amino acids into dipeptides, tripeptides, and polypeptides (proteins).
Amino acid optical activity
All 2-amino acids are optically active EXCEPT glycine (R = H, so no chiral centre — two identical H groups on the central carbon).

✅ Concepts Checklist

🎯 Exam Tips & Common Mistakes

Don't confuse amine classification with alcohol/haloalkane classification
Examiners love testing this. For amines, count substitutions ON THE NITROGEN. (CH₃)₃C-NH₂ is still a PRIMARY amine even though the carbon is "tertiary" — because only one H on the nitrogen has been replaced.
Always explain basicity in terms of the lone pair's "availability"
Don't just say "phenylamine is a weaker base" — you must explain WHY: the lone pair on nitrogen delocalises into the benzene ring's π system, making it less available to accept a proton (form a dative bond with H⁺).
Remember the "excess ammonia" condition
When asked for conditions to make a primary amine from a halogenoalkane, you MUST include "excess" — this is often a required mark point. Without it, secondary/tertiary amines and quaternary salts also form.
The final step in quaternary salt formation has NO HCl
A very common error is writing HCl as a product in every step of the amine + halogenoalkane sequence. In the final step (tertiary amine → quaternary salt), there's no N-H bond left to break, so only the ionic salt forms — no HCl.
Diazotisation temperature: "below 10°C" is a required detail
Simply saying "cold conditions" often won't get full marks. State the specific temperature (below 10°C / using ice) and explain that the diazonium ion decomposes above this temperature.
Zwitterions ≠ neutral molecules with no charge
A zwitterion has BOTH a positive AND a negative charge simultaneously (they just cancel out overall). Don't describe it as having "no charge" — describe it as having balanced positive and negative charges.
When identifying monomers from a polymer, count carbons in the repeat unit carefully
For addition polymers (like poly(ethenol) or poly(prop-2-enoic acid)), the repeating unit only ever has 2 carbons in the main chain backbone. Find where the pattern repeats every 2 carbons, then reverse the C-C single bond back into a C=C double bond to get the monomer.
Amides vs Amines — don't mix up which nitrogen "family" a question is about
Amides (-CONR₂) are much weaker bases than amines because the nitrogen's lone pair is delocalised into the C=O group — this is a subtly different (but related) reason to why aromatic amines are weak bases. If asked to compare, be precise about which effect (ring delocalisation vs carbonyl delocalisation) applies.
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Also in the full note
  • 1. Amines, Amides & Amino Acids — The Family
  • 4. Aromatic Amines — Making & Reacting Phenylamine
  • 6. Condensation & Addition Polymerisation
  • 🎯 Exam Tips & Common Mistakes
  • Solubility & Reaction with Water
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