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Transition Metal Reactions

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Edexcel IAL Chemistry · Unit 5.3

Transition Metal Reactions

Big idea: Transition metals like vanadium, chromium, iron and cobalt can swap between different oxidation states and swap ligands in and out of their structure — and every one of these swaps comes with its own tell-tale colour change, which is exactly what exam questions love to test.

Summary — What This Chapter Covers

  • Vanadium chemistry: four oxidation states (+2 to +5), each with its own colour, reduced step-by-step by zinc.
  • Chromium chemistry: oxidation states +2, +3, +6; the famous yellow ⇌ orange chromate/dichromate equilibrium.
  • Ions in aqueous solution: how metal-aqua ions react with hydroxide and ammonia — precipitates, ligand substitution, and amphoteric behaviour.
  • Catalysts: heterogeneous (different phase, surface adsorption theory) vs homogeneous (same phase, intermediate species).
  • The Contact Process: V₂O₅ as a heterogeneous catalyst that changes oxidation state mid-reaction.
  • Catalytic converters: Pt/Rh catalysts converting car exhaust pollutants.
  • Homogeneous catalysis: Fe²⁺/Fe³⁺ catalysing the iodide–peroxodisulfate reaction.
  • Autocatalysis: Mn²⁺ speeding up its own formation in the manganate(VII)–oxalate reaction.

1. Vanadium Chemistry

Vanadium is unusual because it comfortably exists in four different oxidation states, and — brilliantly for students trying to remember it — every single one has a different, vivid colour. Think of it like a traffic light system, except it has four "lights" instead of three, and they cycle from yellow all the way down to purple as vanadium keeps gaining electrons.

Oxidation StateFormulaNameColour
+5VO₂⁺Dioxovanadium(V)Yellow
+4VO²⁺Oxovanadium(IV)Blue
+3V³⁺Vanadium(III)Green
+2V²⁺Vanadium(II)Purple
Memory trick "Yellow Bus Goes Purple" — VO₂⁺ (Yellow) → VO²⁺ (Blue) → V³⁺ (Green) → V²⁺ (Purple), as you add a reducing agent like zinc and travel down the oxidation states from +5 to +2.

Why does zinc do this?

Zinc metal is a strong reducing agent — it's very willing to lose its own electrons (Zn → Zn²⁺ + 2e⁻), and those electrons have to go somewhere. In acidic conditions, vanadium(V) grabs them one pair at a time, stepping down through +4, +3, and finally +2. Each step is its own separate redox reaction, and each one has a colour change you could watch happen in a test tube — genuinely one of the most visually striking reactions in A Level chemistry.

Using standard electrode potentials (E°) to predict reactions

This is the technique the exam is really testing — not memorising vanadium chemistry, but knowing how to use E° values to work out which reaction happens. Here's the golden rule, stated as simply as possible:

The half-equation with the more positive E° value happens as written (this is the reduction).
The half-equation with the less positive (more negative) E° value gets reversed (this becomes the oxidation). Then balance electrons between the two half-equations and add them together — electrons cancel out completely in the final equation.

Worked example — reducing V⁵⁺ to V⁴⁺ using zinc:

  1. Zn²⁺(aq) + 2e⁻ ⇌ Zn(s)   E° = −0.76 V
  2. VO₂⁺(aq) + 2H⁺(aq) + e⁻ ⇌ VO²⁺(aq) + H₂O(l)   E° = +1.00 V

2. Chromium Chemistry

redox reactions acid-base equilibrium

Redox equationE° value
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Also in the full note
  • 3. Ions in Aqueous Solution
  • 4. Catalysts
  • 5. Autocatalysis
  • What to Memorise
  • Concepts Checklist
  • Exam Tips — Common Mistakes & What Examiners Look For
  • Reduction of Cr(VI) to Cr(III) by zinc — acidic conditions
  • Oxidation of Cr(III) to Cr(VI) by H₂O₂ — alkaline conditions
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