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Organic Analytical Techniques

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Edexcel IAL Chemistry · Unit 4

Organic Analytical Techniques

Every organic molecule leaves behind a unique set of "fingerprints" — in its mass, in how its atoms wobble in a magnetic field, and in how it sticks to different surfaces — and chemists use Mass Spectrometry, NMR, and Chromatography to read those fingerprints and work out exactly what the molecule is.

High-Res Mass Spec ¹³C NMR Low-Res ¹H NMR High-Res ¹H NMR TLC HPLC & GC

Quick Summary — What This Chapter Is Really About

Think of this whole chapter as a detective toolkit. You're given an unknown organic compound and you need to identify it. Each technique gives you a different clue:

  • High Resolution Mass Spectrometry — tells you the exact molecular formula (to 4 decimal places of mass), letting you rule out "look-alike" formulas that have almost the same mass.
  • ¹³C NMR — counts how many different environments exist, and the chemical shift tells you what's attached to each carbon (C=O, C-O, C-Cl, etc).
  • Low resolution ¹H NMR — counts how many different environments exist, and the peak area ratio tells you how many H atoms are in each environment.
  • High resolution ¹H NMR — zooms in further: the splitting pattern of each peak (singlet, doublet, triplet, quartet…) tells you how many H atoms are on the carbon.
  • TLC (Thin-Layer Chromatography) — separates a mixture into spots and uses the Rf value to identify each component by comparing distance travelled.
  • HPLC & GC — more powerful, automated versions of chromatography that separate mixtures and use to identify each component, often used in forensics and drug testing.

By the end, you should be able to look at a set of spectra (MS + NMR) and the full structure of an unknown molecule piece by piece — that's the classic exam question in this topic.

1. High Resolution Mass Spectrometry

Why "high resolution" matters

At AS level, mass spectrometry gave you the molecular ion peak (M⁺) rounded to the nearest whole number, which tells you the approximate Mr. The problem is that lots of different molecular formulas can add up to almost the same whole-number mass. For example, both C₄H₁₀ and C₃H₆O round to an Mr of "58" if you're only working to whole numbers.

Think of it like weighing three people on a bathroom scale that only shows whole kilograms — they might all read "70 kg" even though their actual weights are 69.6 kg, 70.1 kg, and 70.4 kg. A more precise scale (high resolution MS) would separate them instantly.

A high resolution mass spectrometer measures mass accurate to 4 decimal places. Because every element's isotope has a very slightly different exact mass (not a nice round number), formulas that look identical at low resolution become distinguishable at high resolution.

The accurate atomic masses you need

ElementSymbolAccurate Ar
HydrogenH1.0078
CarbonC12.0000
NitrogenN14.0031
OxygenO15.9949

Notice carbon is exactly 12.0000 — that's because the entire relative atomic mass scale is against carbon-12. Every other element's mass is ever-so-slightly off a whole number, and that's exactly the "wobble" high resolution MS is designed to detect.

Method
Accurate Mr = Σ (number of each atom × its accurate Ar)
Calculate this for every candidate formula you're given, then match it against the experimental Mr value from the spectrum. The formula that matches (or is closest) is the correct one.

Worked Example

A compound has an accurate Mr of 58.0417. Is it C₄H₁₀, C₂H₆N₂, or C₃H₆O?

Step 1 — Calculate each candidate:

  • C₄H₁₀ = (4 × 12.0000) + (10 × 1.0078) = 58.0780
  • C₂H₆N₂ = (2 × 12.0000) + (6 × 1.0078) + (2 × 14.0031) = 58.0530
  • C₃H₆O = (3 × 12.0000) + (6 × 1.0078) + 15.9949 = 58.0417

Step 2 — Match: C₃H₆O matches exactly, so that's the molecular formula. Note: this only tells you the formula — it can't tell you whether it's or . You'd need fragmentation data or NMR for that.

📌 Key limitation High resolution MS gives you the molecular formula only — never the structure. C₃H₆O could be propanal (CH₃CH₂CHO) or propanone (CH₃COCH₃). You always need a second technique (usually NMR) to pin down the actual arrangement of atoms.
Practice Question
A compound has an accurate Mr of 44.0262. Determine whether it is C₂H₄O, C₂H₆N, or CH₄N₂. Show your working.

2. Carbon-13 (¹³C) NMR Spectroscopy

The basic idea

Most carbon atoms in nature are carbon-12, which has an even mass number and does show up on NMR. But a small natural fraction of carbon atoms are carbon-13 — an isotope with an odd mass number, which produce a signal.

In ¹³C NMR, we measure the magnetic environment of every carbon-13 nucleus in the molecule, plot it on a spectrum, and compare it all against a standard reference compound: Tetramethylsilane (TMS), which is set at 0 ppm.

Imagine every carbon atom is a person standing in a room, and the "room" is defined by what's directly bonded to it (a C=O group, an OH group, a benzene ring...). Carbons in identical rooms (identical chemical environments) give exactly the same signal. Carbons in different rooms show up at different points on the spectrum.

Chemical shift table (memorise the ranges, not exact numbers)

Environment of carbonGroupsShift range δ / ppm
−CH₂−CH₂−Alkyl5 – 40
RCH₂Cl or BrHalogenoalkanes10 – 70
RCOCH₂−Carbonyls20 – 50
RCH₂NH₂Amines25 – 60
−CH₂−O−Alcohols, ethers, esters50 – 90
−CH=CH−Alkenyl90 – 150
R−C≡NNitriles110 – 125
C₆H₆Benzene110 – 160
R−COO−Ester or acid160 – 185
R−CO−Aldehyde or ketone190 – 220

Notice the pattern: the more electronegative / double-bonded the neighbours, the further right (higher ppm) the signal appears. Carbonyls (C=O) sit way out at 190–220 ppm because oxygen pulls electron density away hard.

Key features of a ¹³C spectrum

  • Displays sharp single signals — no splitting into sub-peaks like ¹H NMR shows.
  • The height of each peak is NOT proportional to the number of carbons in that environment — unlike ¹H NMR, you cannot use peak size to count atoms.
  • Different chemical environments give different chemical shifts.
  • TMS is still the 0 ppm reference.

Worked Example — Propanone

Propanone is CH₃–CO–CH₃. Both CH₃ groups are chemically identical (the molecule is symmetrical), so there are only 2 molecular environments: the two equivalent CH₃ carbons, and the single C=O carbon.

Result: the ¹³C NMR spectrum shows 2 peaks — one around 30 ppm (CH₃, alkyl) and one around 205 ppm (C=O, ketone).

💡 Exam strategy Whenever you're asked "how many peaks/environments," the very first move is to draw the molecule and look for symmetry. Any atoms related by a mirror plane or rotational symmetry are equivalent and give just ONE peak between them.
Practice Question
How many chemical environments (and therefore ¹³C NMR peaks) would you expect for 1,4-dihydroxybenzene (para isomer, OH groups directly opposite each other)?

3. Low Resolution Proton (¹H) NMR

Same idea, now with hydrogen

¹H NMR works on exactly the same principle as ¹³C NMR, but now we're detecting hydrogen nuclei (protons) instead of carbon-13. Again, TMS is the reference at 0 ppm — chosen because it's non-toxic, doesn't react with the sample, has a low boiling point (easy to remove afterwards), and gives one single sharp peak.

The big difference from ¹³C NMR: in ¹H NMR, the area under each peak IS proportional to the number of protons in that environment. This is a huge advantage — it means peak area (measured by an "integration trace") tells you the ratio of H atoms directly.

Chemical shift table for ¹H environments

EnvironmentShift range δ / ppm
ROH0.5 – 5.5
RCH₃0.7 – 1.2
RNH₂1.0 – 4.5
R₂CH₂1.2 – 1.4
R₃CH1.4 – 1.6
RCOCH−2.1 – 2.6
ROCH−3.1 – 3.9
RCH₂Cl or Br3.1 – 4.2
RCOOCH−3.7 – 4.1
RC=CH−4.5 – 6.0
RCHO9.0 – 10.0
RCOOH10.0 – 12.0

You'll be given a data sheet with these values in the actual exam — you don't need to memorise exact numbers, but you should recognise the rough order: alkyl CH is furthest left (low ppm), carboxylic acid OH is furthest right (high ppm, most deshielded).

Worked Example — Ethanol

Ethanol, CH₃CH₂OH, has 3 chemical environments: −CH₃, −CH₂, and −OH.

So the low resolution ¹H NMR spectrum shows 3 peaks, at roughly:

  • 1.2 ppm → −CH₃ (3 protons)
  • 3.7 ppm → −CH₂ (2 protons)
  • 5.4 ppm → −OH (1 proton)

The areas of these three peaks are in the ratio 3 : 2 : 1, matching the number of H atoms in each environment. This ratio is exactly what a real spectrum's integration trace would show you.

🔑 Chemically equivalent protons Protons count as being in the "same environment" if they're chemically equivalent — for example, in 1,2-dichloroethane (Cl-CH₂-CH₂-Cl), all four H atoms are identical by symmetry, so the whole molecule gives just ONE single peak, even though there are 4 hydrogens.
Practice Question
Propan-1-ol has the structure CH₃CH₂CH₂OH. How many peaks would you expect in its low resolution ¹H NMR spectrum, and what would the ratio of peak areas be?

4. High Resolution Proton (¹H) NMR — Splitting Patterns

Zooming in for more detail

A low resolution spectrum only tells you exist and are in each. A high resolution spectrum reveals something extra: each peak is actually made of tiny sub-peaks clustered together, called a splitting pattern.

This splitting is caused by a proton's nuclear spin "feeling" the spins of protons on the adjacent (neighbouring) carbon atom. It's like each nearby proton nudges the signal slightly, and the number of nudges tells you exactly how many protons are next door.

The n+1 Rule
Number of sub-peaks = n + 1
where n = the number of protons on the carbon atom(s) to the one producing the signal. Important: protons on the SAME carbon, and the OH proton itself, don't count towards splitting — only neighbours.

Splitting patterns to recognise

Adjacent protons (n)Pattern (n+1)Intensity ratio
0Singlet (1 peak)1
1Doublet (2 peaks)1 : 1
2Triplet (3 peaks)1 : 2 : 1
3Quartet (4 peaks)1 : 3 : 3 : 1

Notice the intensity ratios follow Pascal's triangle — a nice pattern-spotting shortcut if you already know it from maths!

Worked Example — Ethanol (high resolution)

Take the same three environments from before and now look at splitting:

  • −OH peak: appears as a singlet. This is a special exception — because the OH proton rapidly exchanges with trace water in the sample, it doesn't experience consistent coupling with its neighbours, so it never splits (you just need to know this as a fact).
  • −CH₂− peak: the adjacent carbon (CH₃) has 3 protons, so n=3, giving 3+1 = 4 peaks (quartet).
  • −CH₃ peak: the adjacent carbon (CH₂) has 2 protons, so n=2, giving 2+1 = 3 peaks (triplet).

This quartet + triplet combination is extremely common — it's the signature of an ethyl group, CH₃CH₂−, and you should learn to spot it instantly.

Splitting patterns always come in pairs — each proton splits the signal of its neighbour, and vice versa. If CH₂ is a quartet because of 3 neighbouring H's on CH₃, then CH₃ must be a triplet because of 2 neighbouring H's on CH₂. They "talk" to each other symmetrically.

Integrated spectra — the full picture

A complete high resolution spectrum combines three pieces of information for each signal:

  1. Chemical shift (δ) — tells you the type of environment (from the data table)
  2. Integration / relative peak area — tells you how many H atoms are in that environment
  3. Splitting pattern — tells you how many H atoms are on the adjacent carbon

For methyl chloroethanoate, ClCH₂COOCH₃, the integration ratio is 2:3 (2H in CH₂, 3H in CH₃) — but note these two groups aren't adjacent to each other (there's a C=O and O in between), so neither peak splits the other — both would appear as singlets!

⚠️ Common trap Students often assume ANY two groups on a molecule will split each other. They only split each other if they're on directly adjacent carbons. If there's a carbon with no attached H, a C=O, or an oxygen in between, the coupling doesn't reach across — you get a singlet instead.
Practice Question
For (CH₃)₂CHOH, predict: (i) number of peaks, (ii) relative peak areas, (iii) the splitting pattern of each peak.

5. Chromatography — Thin-Layer Chromatography (TLC)

The core principle behind ALL chromatography

Every chromatography technique (TLC, column, HPLC, GC) works on the same idea: a mixture is dissolved in a mobile phase (a fluid that moves), which flows through or over a stationary phase (a fixed material). Different components of the mixture interact with the stationary phase to different extents — some cling on tightly (high retention), some barely interact at all and race ahead with the mobile phase.

Imagine a crowd of people walking through a room full of sticky flypaper strips hanging from the ceiling (the stationary phase), being gently blown forward by a fan (the mobile phase). People wearing very sticky clothes get caught and slowed down a lot; people in slippery raincoats zoom straight through. After a while, the crowd has spread out — and how far each person travelled tells you something about how "sticky" they are.
TechniqueStationary phaseMobile phase
Thin-layer (TLC)Solid silica on plastic/glass plateLiquid solvent (water or organic)
Column (CC)Solid silicaLiquid solvent
Gas-Liquid (GLC)Microscopic liquid film on solid supportInert carrier gas (e.g. nitrogen)

Running a TLC analysis, step by step

  1. Prepare a beaker with a small quantity of solvent.
  2. On the TLC plate, draw a horizontal baseline near the bottom edge — in pencil, never pen (pen ink would dissolve and interfere with the results).
  3. Spot pure reference compounds and the unknown sample mixture onto the baseline, and let them air dry.
  4. Stand the plate in the beaker of solvent, making sure the solvent level stays below the spots. Cover with a lid so the solvent atmosphere stays saturated.
  5. As the solvent rises up the plate by capillary action, it carries the dissolved components with it at different rates. When the solvent nears the top, remove the plate and immediately mark the solvent front in pencil.
  6. If the spots are colourless, visualise them using UV light, iodine vapour, or ninhydrin (a carcinogen, used carefully).
Retention Factor
Rf = (distance travelled by component) ÷ (distance travelled by solvent)
Rf values are always between 0 and 1. A compound that barely moves has Rf close to 0 (strong interaction with stationary phase); a compound that travels almost with the solvent front has Rf close to 1 (weak interaction, more soluble in mobile phase). Compare your calculated Rf against known reference values to identify the compound.
Practice Question
On a TLC plate, the solvent front travels 8.4 cm from the baseline. A spot travels 5.88 cm. Calculate the Rf value, and state what it tells you about that compound's interaction with the stationary phase.
📌 Why pencil, always Pen ink is itself a mixture of coloured, soluble compounds. If you used pen for the baseline, the ink would dissolve into the solvent and run up the plate right alongside your sample — contaminating your results with extra unwanted spots. Pencil (graphite) is insoluble and inert, so it stays put.

6. Chromatography — HPLC & GC

Column chromatography — the starting point

In column chromatography, a vertical tube (like a burette) is packed with an inert solid stationary phase (silica gel or alumina), saturated with solvent. The sample is carefully added to the top without disturbing the packed surface, then more solvent (eluent) is continually added on top to keep pushing everything through.

Gravity pulls everything down through the column — components with the strongest affinity for the stationary phase move the slowest and come out last; components with the weakest affinity flow through fastest and come out first.

HPLC — High Performance Liquid Chromatography

HPLC is essentially column chromatography, souped up:

  • The sample is pumped through under pressure rather than relying on gravity — much faster.
  • The stationary phase particles are much smaller, giving a bigger surface area and therefore sharper, better separation.
  • A detector sits at the end of the column and measures retention time — the time from injection to detection.
  • The whole process is automated and linked to a computer that can instantly compare results against a database of known compounds.

GLC / GC — Gas-Liquid Chromatography

GLC is used for analysing gases, volatile liquids, and solids that can be vaporised. Key differences from liquid-based methods:

  • Stationary phase: a thin film of non-volatile liquid coated inside a long coiled column.
  • Mobile phase: an inert carrier gas (e.g. helium or nitrogen) — inert so it doesn't react with the sample.
  • The sample is injected through a self-sealing disc and vaporises, then travels through the column carried by the gas.

Just like HPLC, each component reaches the detector at its own characteristic retention time, and the resulting chromatogram shows a series of peaks — one per compound present.

Reading a chromatogram
Peak position = identity · Peak area = quantity
Retention time (x-axis position of the peak) identifies WHICH compound it is, by comparison with known reference retention times. Peak area/height (how big the peak is) tells you HOW MUCH of that compound is present relative to the others.

Worked Example

A GLC trace of a compound shows four peaks: A, B, C, D — with D being the tallest and appearing at the longest retention time, and B and C being equal-sized smaller peaks.

  • Which compound is present in the greatest quantity? → D (largest peak area = greatest quantity)
  • Which compounds are present in equal amounts? → B and C (equal peak sizes)
  • Which compound interacts most strongly with the stationary phase? → D (longest retention time = spent the most time "stuck" to the stationary phase)

Uses and limitations

Common uses: forensic evidence, drug testing in sport, environmental pollution monitoring, detecting explosives in baggage.

The big limitation: HPLC and GC alone cannot give in a legal sense, because:

  • Different compounds can coincidentally have the same retention time.
  • Conditions like temperature and pressure are hard to keep perfectly controlled, which shifts retention times.
  • Some unknown compounds simply have no reference data in the database to compare against.

That's why HPLC and GC are almost always coupled with mass spectrometry — giving HPLC-MS and GC-MS. This lets you separate the mixture AND get a definitive mass-spectrum fingerprint of each component, all in one machine run.

🏅 Real-world case: nandrolone drug testing GC-MS is the standard method for detecting the anabolic steroid nandrolone in athletes via its metabolite, 19-norandrosterone. A urine concentration above 2 nanograms per cm³ (0.000000002 g per cm³) counts as a positive test. This shows just how incredibly sensitive these techniques are — detecting mass differences and trace concentrations far beyond what's humanly measurable by other means.
Practice Question
Explain why GC-MS is considered more reliable for legal drug testing than GC alone.

What to Memorise

High-Res Mass Spec

  • Accurate Ar: H=1.0078, C=12.0000, N=14.0031, O=15.9949
  • High res MS gives molecular formula, NOT structure
  • If your calc doesn't match exactly, pick the closest value

¹³C NMR

  • TMS = reference, 0 ppm
  • Sharp singlet peaks — no splitting
  • Peak height NOT proportional to carbon count
  • C=O carbonyls: 190–220 ppm (furthest right)

Low-Res ¹H NMR

  • TMS = reference, 0 ppm
  • Peak AREA is proportional to number of H atoms
  • Count environments first — look for symmetry

High-Res ¹H NMR

  • n+1 rule: peaks = (adjacent H atoms) + 1
  • Singlet(1) / Doublet(2) / Triplet(3) / Quartet(4)
  • Intensity ratios: 1:1 / 1:2:1 / 1:3:3:1
  • OH proton is always a singlet (proton exchange)
  • Splitting only happens between adjacent carbons

TLC

  • Rf = distance by component ÷ distance by solvent
  • Baseline drawn in PENCIL, never pen
  • Solvent level must stay below the sample spots

HPLC & GC

  • Retention time = identity clue
  • Peak area/height = quantity clue
  • GLC mobile phase = inert gas (He, N₂)
  • Coupled with MS for definitive identification

Concepts Checklist

Exam Tips & Common Mistakes

Don't confuse molecular formula with structure. High resolution MS answers "what atoms and how many?" — it never answers "how are they arranged?" Examiners love setting this trap by asking you to identify a compound from Mr alone and then asking if you're "certain" of the structure. You're not — you need NMR too.
Splitting comes from NEIGHBOURING carbons only — not the same carbon. A very common error is counting protons on the SAME carbon as the signal when applying n+1. Always ask: "how many H atoms are on the carbon(s) directly bonded to this one?"
Remember the OH exception. Even though OH has neighbouring carbons with protons, it shows up as a singlet due to rapid proton exchange with trace water — this is a "learn it as a fact" exception the examiners test directly.
¹³C peak height ≠ quantity, but ¹H peak AREA = quantity. Mixing these two up is one of the most common marks lost in this topic. ¹³C tells you WHICH environments exist (via shift) but not how many carbons in each; ¹H tells you both which AND how many (via integration).
Always draw the molecule and mark symmetry before counting peaks. Whether it's ¹H or ¹³C NMR, the fastest way to correctly count environments is to physically sketch the structure and circle groups of equivalent atoms.
TLC baseline must be pencil — this is an easy mark examiners test directly. Also remember the solvent level must stay below the spotted samples, or your compounds will just dissolve straight into the beaker instead of separating up the plate.
"Identify the compound with the greatest quantity" = biggest peak AREA (or height), not longest retention time. Retention time tells you WHICH compound / how strongly it interacted with the stationary phase — it does not tell you how much of it is present.
When asked to justify using multiple techniques together (e.g. GC-MS, or "MS and NMR together"), always explain the SPECIFIC limitation of the single technique that the second one fixes — don't just say "for more information," name exactly what information is missing and how the second technique supplies it.
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