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Chemistry (IAL)

Organic Chemistry: Carboxylic Acids

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  Edexcel IAL Chemistry — Organic Chemistry

Carboxylic Acids

Big idea: carboxylic acids are the "–COOH" family — weak, hydrogen-bonded acids that can be made from alcohols, aldehydes or nitriles, and turned into salts, esters, acyl chlorides or amides depending on what you react them with.

Summary — the whole chapter in one scroll

  • What they are: compounds containing the –COOH functional group, general formula CnH2n+1COOH (shortened RCOOH).
  • Physical properties: high melting/boiling points because of hydrogen bonding; short-chain ones dissolve in water, but solubility drops as the carbon chain gets longer.
  • How to make them: (1) oxidise a primary alcohol or aldehyde with acidified KMnO₄ or K₂Cr₂O₇ under reflux, or (2) hydrolyse a nitrile with dilute acid or dilute alkali (+ acidification).
  • Reactions: weak acid behaviour with carbonates/bicarbonates (fizzes CO₂ — a classic test), reduction with LiAlH₄ to primary alcohols, reactions with metals/alkalis/carbonates to form salts, reaction with PCl₅ to form acyl chlorides, and condensation with alcohols to form esters.
  • Acyl chlorides & esters: acyl chlorides are super-reactive carboxylic acid derivatives (–COCl) that undergo nucleophilic addition–elimination with water (→ carboxylic acid), alcohols (→ esters), and ammonia/amines (→ amides + ammonium salt).
  • Ester hydrolysis: acid hydrolysis is reversible (equilibrium, doesn't go to completion); alkaline hydrolysis is irreversible (goes to completion, gives a carboxylate salt that needs acidifying to get the acid back).
  • Polyesters: condensation polymers made from a diol + a dicarboxylic acid (or a single hydroxycarboxylic acid), linked by ester bonds, releasing water at every link.

1. Carboxylic Acids — Structure & Physical Properties

Functional group Boiling points Solubility

Every carboxylic acid has the –COOH group sitting at the end of a carbon chain. Think of it as a carbon double-bonded to one oxygen (like a ketone) and single-bonded to an –OH group, both attached to the same carbon. That carbon is always numbered carbon 1 — which is why you never need locant numbers in the name (unlike "propan-2-ol" or similar).

Naming pattern

Carboxylic acids are named: alkan + oic acid. So the 2-carbon chain (ethane) becomes ethanoic acid, the 3-carbon chain (propane) becomes propanoic acid, and so on. Some countries call the whole family "alkanoic acids" instead of "carboxylic acids" — same thing.

StructureNameMolecular Formula
HCOOHMethanoic acid (formic acid)HCOOH
CH₃COOHEthanoic acid (acetic acid)CH₃COOH
CH₃CH₂COOHPropanoic acidCH₃CH₂COOH

Why the boiling points are so high

Carboxylic acids contain two polarised groups: the C=O and the O–H. Because of the O–H bond, molecules can form hydrogen bonds with each other — and in fact, two carboxylic acid molecules can pair up into a "dimer," hydrogen-bonding to each other at both ends like a molecular handshake. That's a lot of intermolecular attraction to break, which is why carboxylic acids have unusually high melting and boiling points for their size — often higher than alcohols of similar molar mass.

Rule to remember More hydrogen bonding = more energy needed to separate molecules = higher boiling point. Carboxylic acids > alcohols > alkanes of similar chain length, in terms of boiling point.

Solubility — and why it fades with chain length

The same O–H group that gives high boiling points also lets short-chain carboxylic acids hydrogen-bond with water molecules — so methanoic, ethanoic and propanoic acid mix with water in any proportion. But as the hydrocarbon "tail" gets longer, it starts wedging itself between water molecules, physically breaking up the water's own hydrogen-bond network. The tail is non-polar and water can't hydrogen bond to it, so solubility drops off. Acids with more than 8 carbons are solids at room temperature and barely dissolve in cold water (though hot water helps a bit).

Analogy Imagine water molecules as people holding hands in a circle (hydrogen bonds). A short carboxylic acid molecule is small enough to squeeze into the circle and still hold hands with two people either side. A long-chain one is like trying to fit a broom handle into the circle — it breaks the hand-holding without being able to hold hands back along most of its length.
Practice Question

Explain why butanoic acid has a higher boiling point than butan-1-ol, even though both molecules have similar chain lengths and both can hydrogen bond.

2. Preparation of Carboxylic Acids

Oxidation route Nitrile hydrolysis route

Route 1: Oxidation of primary alcohols & aldehydes

Primary alcohols oxidise in two stages: first to an aldehyde, then all the way to a carboxylic acid. Aldehydes can also be oxidised straight to carboxylic acids in a single step. The oxidising agent is either acidified potassium dichromate(VI), K₂Cr₂O₇, or acidified potassium manganate(VII), KMnO₄ — always under reflux, so that the volatile intermediate doesn't escape before it's fully oxidised.

CH₃CH₂OH --[O]--> CH₃CHO --[O]--> CH₃COOH
(ethanol, primary alcohol) → (ethanal, aldehyde) → (ethanoic acid)

You can spot that oxidation is happening because the oxidising agent itself gets reduced, and that shows up as a colour change:

  • K₂Cr₂O₇: orange dichromate ions (Cr₂O₇2−) → green Cr3+ ions
  • KMnO₄: purple manganate ions (MnO₄) → colourless Mn2+ ions
Key distinction Reflux + excess oxidising agent = full oxidation to carboxylic acid. (If you wanted to stop at the aldehyde, you'd use gentle heating with distillation instead — removing the aldehyde as it forms, before it oxidises further. That's a different technique covered elsewhere, but it's useful to remember why reflux matters here.)

Route 2: Hydrolysis of nitriles

A nitrile has a –C≡N group. Hydrolysing it (breaking it apart with water, using either dilute acid or dilute alkali) converts the –CN into a –COOH group, adding one carbon's worth of carboxylic acid onto the chain.

  • Acid hydrolysis (dilute HCl + water, heat): gives the carboxylic acid directly, plus an ammonium salt as a by-product.
  • Alkaline hydrolysis (dilute NaOH + water, heat): gives a sodium carboxylate salt plus ammonia gas — you then need a separate acidification step to convert the carboxylate salt into the actual carboxylic acid.
Acid route: CH₃CH₂C≡N + HCl + 2H₂O → CH₃CH₂COOH + NH₄Cl
Alkali route: CH₃CH₂C≡N + NaOH + H₂O → CH₃CH₂COONa + NH₃
then: CH₃CH₂COONa + HCl → CH₃CH₂COOH + NaCl (acidification step)
Memory hook Acid hydrolysis of a nitrile = one-step, straight to the acid. Alkaline hydrolysis = two-step (salt first, then acidify) — because NaOH is a base, so the acidic –COOH that would form immediately reacts with any excess NaOH to make the salt instead.
Practice Question

Propanenitrile (CH₃CH₂C≡N) is refluxed with dilute sodium hydroxide, then the mixture is acidified with dilute hydrochloric acid. Name the final organic product and write a balanced equation for each stage.

3. Reactions of Carboxylic Acids

Weak acid Reduction Salt formation

Carboxylic acids are weak acids

In water, carboxylic acids only partially ionise:

CH₃COOH ⇌ CH₃COO⁻ + H⁺

The equilibrium sits well over to the left, meaning most molecules stay as CH₃COOH — only a small fraction ionises to give H⁺ and the carboxylate ion (CH₃COO⁻). That's exactly what "weak acid" means: not fully dissociated (compare with strong acids like HCl, which ionise essentially completely).

Common mistake "Weak acid" does not mean "dilute acid." Weak/strong refers to how much the acid ionises; concentrated/dilute refers to how much water it's mixed with. You can have a concentrated weak acid or a dilute strong acid — they're independent ideas!

The carbonate test — a classic identification reaction

Even though the H⁺ concentration is low, it's still enough to react with carbonates and hydrogen carbonates, producing fizzing CO₂ gas. This is a genuinely useful lab test: if bubbling/fizzing occurs with sodium carbonate or sodium bicarbonate solution, you likely have a carboxylic acid (or another acid) present.

ReagentEquation
Sodium carbonate2RCOOH + Na₂CO₃ → 2RCOO⁻Na⁺ + CO₂ + H₂O
Ionic (carbonate)2RCOOH + CO₃²⁻ → 2RCOO⁻ + CO₂ + H₂O
Sodium hydrogen carbonateRCOOH + NaHCO₃ → RCOO⁻Na⁺ + CO₂ + H₂O
Ionic (hydrogen carbonate)RCOOH + HCO₃⁻ → RCOO⁻ + CO₂ + H₂O

Reduction with LiAlH₄

Lithium tetrahydridoaluminate (LiAlH₄) is a powerful reducing agent — used suspended in dry ether at room temperature (not water, because LiAlH₄ reacts violently with water). It reduces a carboxylic acid all the way down to a primary alcohol.

Equation to know CH₃CH₂COOH (l) + 4[H] → CH₃CH₂CH₂OH (l) + H₂O (l)

Notice it takes 4 [H] — more than the 2[H] you'd use to reduce an aldehyde to an alcohol — because you're removing an oxygen as well as adding hydrogens. Water is added at the very end of the reaction simply to destroy/quench any leftover LiAlH₄ safely.

Reaction with bases: metal oxides, alkalis, carbonates

Carboxylic acids behave like any other acid when reacting with these three types of base — the products just follow the standard acid + base rules you already know:

Base typeProductsExample
Metal oxideSalt + water2CH₃COOH + MgO → (CH₃COO)₂Mg + H₂O
AlkaliSalt + water (neutralisation)CH₃COOH + KOH → CH₃COOK + H₂O
CarbonateSalt + water + CO₂2CH₃COOH + K₂CO₃ → 2CH₃COOK + H₂O + CO₂

Reaction with phosphorus(V) chloride, PCl₅

Solid PCl₅ converts a carboxylic acid into an acyl chloride — this is actually one of the standard ways to make acyl chlorides in the lab. You get "steamy fumes" of HCl gas as a visible sign the reaction is happening (a classic exam observation to quote!).

CH₃CH₂COOH (l) + PCl₅ (s) → CH₃CH₂COCl (l) + POCl₃ (l) + HCl (g)

The three liquid/gas products (acyl chloride, phosphorus trichloride oxide, HCl) can be separated by fractional distillation because they have different boiling points.

Reaction with alcohols → esters (esterification)

Heating a carboxylic acid with an alcohol, using concentrated H₂SO₄ as a catalyst, gives an ester in a condensation reaction (water is eliminated). Naming is a two-part job: the first part comes from the alcohol, the second part from the acid.

CH₃CH₂CH₂OH + CH₃COOH ⇌ CH₃CH₂CH₂-O-COCH₃ + H₂O
(propan-1-ol + ethanoic acid ⇌ propyl ethanoate + water)
Naming trick "Propyl ethanoate" — propyl comes from the alcohol (propanol), ethanoate comes from the acid (ethanoic acid). Read it backwards to reconstruct the reactants: "...oate" tells you the acid, the bit before tells you the alcohol.
Practice Question

Ethanoic acid is added to solid sodium carbonate. (a) State the observation you would make. (b) Write the ionic equation for the reaction.

Practice Question

Butanoic acid, CH₃CH₂CH₂COOH, is reduced using excess LiAlH₄ in dry ether. Write the equation for this reaction and name the organic product.

4. Acyl Chlorides & Esters

Very reactive Addition–elimination

Acyl chlorides (–COCl) and acid anhydrides are both "derivatives" of carboxylic acids — made by swapping out the –OH group for something else (a Cl atom for acyl chlorides, or an alkanoate group for anhydrides). Naming follows the same pattern as the parent acid, but swaps "-oic acid" for "-oyl chloride" or "-oic anhydride."

Parent acidAcyl chlorideAcid anhydride
Ethanoic acid, CH₃COOHEthanoyl chloride, CH₃COClEthanoic anhydride, (CH₃CO)₂O

The mechanism pattern: nucleophilic addition–elimination

Acyl chlorides are much more reactive than carboxylic acids because Cl is a great leaving group. Almost every reaction of an acyl chloride follows the same two-step pattern:

  1. Addition — a nucleophile (water, an alcohol, or ammonia/an amine) attacks and adds across the C=O bond.
  2. Elimination — a small molecule (HCl, or a Cl⁻ ion that quickly becomes HCl) is kicked out.
One mechanism, three products + H₂O → carboxylic acid + HCl
+ alcohol → ester + HCl
+ ammonia/amine → amide + HCl (which then gets mopped up as an ammonium salt)

Hydrolysis (with water)

CH₃CH₂COCl + H₂O → CH₃CH₂COOH + HCl
(propanoyl chloride → propanoic acid)

Formation of esters (with alcohols)

CH₃CH₂COCl + CH₃CH₂OH → CH₃CH₂COOCH₂CH₃ + HCl
(propanoyl chloride + ethanol → ethyl propanoate)

This route (acyl chloride + alcohol) is actually a better way to make esters in the lab than the carboxylic acid + alcohol route, because it's faster, doesn't need a catalyst, and doesn't set up a reversible equilibrium — it goes essentially to completion.

Formation of amides (with ammonia or amines)

This one has an extra twist. A lone pair on the nitrogen attacks the carbonyl carbon (same addition–elimination idea), and a Cl⁻ is eliminated, forming HCl. But that HCl doesn't just sit there — it's immediately neutralised by a second molecule of ammonia or amine (which must be present in excess), forming an ammonium salt.

Why you need 2 molecules of ammonia/amine Molecule #1 reacts with the acyl chloride to form the amide.
Molecule #2 mops up the HCl by-product to form an ammonium salt (e.g. NH₄Cl).
That's why every acyl chloride + amine equation has a "2" in front of the amine!
ReagentProductEquation
AmmoniaPrimary amide + ammonium chlorideCH₃CH₂COCl + 2NH₃ → CH₃CH₂CONH₂ + NH₄Cl
MethylamineSecondary amide + methylammonium chlorideCH₃COCl + 2CH₃NH₂ → CH₃CONHCH₃ + CH₃NH₃Cl
Examiner tip Acyl chlorides react with primary amines → secondary amide + HCl, and with secondary amines → tertiary amide + HCl. They do not react with tertiary amines (no N–H/lone pair available in the right way to continue the mechanism as expected... more precisely, tertiary amines have no H to lose, so they can't form a stable amide product this way).
Practice Question

Ethanoyl chloride reacts with excess ethylamine (CH₃CH₂NH₂). Write the equation and name both products.

5. Acid & Alkaline Hydrolysis of Esters

Reversible vs irreversible

Hydrolysis is literally the reverse of esterification — breaking the ester bond apart using water, with either acid or alkali as a catalyst/reagent. Which one you use completely changes how the reaction behaves.

Acid hydrolysis — reversible, equilibrium

Heating an ester under reflux with dilute acid (e.g. dilute H₂SO₄) sets up an equilibrium — the reaction does not go to completion, meaning at any moment you have a mixture of ester + water and carboxylic acid + alcohol.

CH₃CH₂COOCH₂CH₃ + H₂O ⇌ CH₃CH₂COOH + CH₃CH₂OH
(ethyl propanoate ⇌ propanoic acid + ethanol)

Alkaline hydrolysis — irreversible, goes to completion

Heating an ester under reflux with dilute alkali (e.g. NaOH) is irreversible — the ester is fully hydrolysed. But there's a catch: the direct product isn't the carboxylic acid, it's the sodium carboxylate salt (because the acidic –COOH that would form immediately reacts with the excess NaOH present). If you actually want the carboxylic acid itself, you need a separate acidification step afterwards.

CH₃CH₂COOCH₂CH₃ + NaOH → CH₃CH₂COONa + CH₃CH₂OH
(ethyl propanoate + NaOH → sodium propanoate + ethanol)

then, if needed: CH₃CH₂COONa + HCl → CH₃CH₂COOH + NaCl
Acid hydrolysisAlkaline hydrolysis
Reaction typeEquilibrium — does NOT go to completionIrreversible — goes to completion
ConditionsReflux, heat, dilute acid (HCl or H₂SO₄)Reflux, heat, dilute alkali (NaOH)
ProductsCarboxylic acid + alcoholCarboxylate salt + alcohol
Why the difference? In acid conditions there's no base around to "steal" the H⁺ from the –COOH, so it stays as the neutral acid — but since it's an equilibrium (H₂SO₄/HCl is just a catalyst, water is a reagent in modest supply), it never fully converts. In alkaline conditions, the OH⁻ actively deprotonates the carboxylic acid as fast as it forms, which pulls the equilibrium all the way to completion (Le Chatelier's principle in action) — but leaves you with the salt, not the acid.
Practice Question

Methyl propanoate is heated under reflux with hot sodium hydroxide solution. Name the products and write the balanced equation.

Practice Question

Explain why hydrolysing an ester with dilute sulfuric acid does not produce a pure sample of carboxylic acid, even after a long reflux time.

6. Forming Polyesters

Condensation polymerisation

Addition polymers (like polyethene) are built from monomers with C=C double bonds joining together with nothing lost. Condensation polymers work differently: monomers link together with a small molecule (usually water) eliminated at every join. You can spot a condensation polymer because the repeating monomers are connected by ester bonds (→ polyester) or amide bonds (→ polyamide, like nylon — covered elsewhere).

Route 1: diol + dicarboxylic acid

A polyester needs two things reacting repeatedly:

  • A diol — a molecule with 2 –OH groups, one at each end (e.g. ethane-1,2-diol).
  • A dicarboxylic acid — a molecule with 2 –COOH groups, one at each end (e.g. benzene-1,4-dicarboxylic acid).

Every time an –OH end reacts with a –COOH end, an ester bond forms and a water molecule is eliminated. Because both monomers have functional groups at both ends, the chain can just keep growing and growing — that's what makes it a polymer rather than a single small molecule.

n HO-CH₂CH₂-OH + n HOOC-C₆H₄-COOH → [-O-CH₂CH₂-O-CO-C₆H₄-CO-]ₙ + 2n H₂O
(ethane-1,2-diol + benzene-1,4-dicarboxylic acid → PET + water)

The example in the chapter is exactly this reaction — it produces poly(ethylene terephthalate), PET, which you'll know by its trade names Terylene or Dacron (used in polyester fabric and plastic bottles).

Route 2: a single hydroxycarboxylic acid

Instead of using two separate monomers, you can use one monomer that already has both functional groups — an –OH at one end and a –COOH at the other. This is called a hydroxycarboxylic acid (e.g. 2-hydroxybutanoic acid). Since each individual molecule has one of each group, they can link up head-to-tail indefinitely, again releasing water at every ester bond formed.

Two monomers vs one monomer Diol + dicarboxylic acid → alternating pattern (A-B-A-B...) because you need one of each.
Single hydroxycarboxylic acid → every monomer is identical, and each one supplies both ends of its own ester link.
Spotting the pattern in an exam To identify what monomer(s) built a given polyester, look at the repeat unit and find the ester link -C(=O)-O-. Everything on one side of it (up to the next ester link) traces back to one monomer. If the two "halves" either side of each ester link look the same, it's from a single hydroxycarboxylic acid; if they alternate between two different structures, it's from a diol + dicarboxylic acid pair.
Practice Question

Draw (in words/formula) the repeat unit formed when ethane-1,2-diol reacts with benzene-1,4-dicarboxylic acid, and state what small molecule is eliminated at each ester link.

Practice Question

2-hydroxybutanoic acid can polymerise on its own to form a polyester. Explain why this single monomer is capable of forming a polymer chain, whereas a simple carboxylic acid like propanoic acid cannot.

What to Memorise

Carboxylic acid
Compound containing –COOH; general formula RCOOH. Weak acid, partially ionises in water.
Weak acid
Only partially dissociates in solution — equilibrium lies to the left. Not the same as "dilute."
Oxidation (alcohol/aldehyde → acid)
Acidified KMnO₄ or K₂Cr₂O₇, under reflux. Colour change: orange→green (dichromate) or purple→colourless (manganate).
Nitrile hydrolysis
Dilute acid → acid + ammonium salt directly. Dilute alkali → carboxylate salt + NH₃, then needs acidifying.
LiAlH₄ reduction
Dry ether, room temp. RCOOH + 4[H] → RCH₂OH + H₂O. Reduces acid to primary alcohol.
PCl₅ reaction
RCOOH + PCl₅ → RCOCl + POCl₃ + HCl. "Steamy fumes" of HCl observed.
Esterification
Acid + alcohol, conc. H₂SO₄ catalyst, condensation reaction (reversible).
Acyl chloride
–COCl group. Very reactive; undergoes nucleophilic addition–elimination with water/alcohols/amines.
Addition–elimination
Nucleophile adds across C=O, then a small molecule (HCl) is eliminated. Core mechanism for acyl chloride reactions.
2 molecules of amine rule
One amine molecule forms the amide; a second neutralises the HCl by-product to form an ammonium salt.
Acid vs alkaline ester hydrolysis
Acid = reversible equilibrium, gives acid + alcohol. Alkali = irreversible, gives carboxylate salt + alcohol.
Polyester formation
Diol + dicarboxylic acid, or single hydroxycarboxylic acid. Ester links form, water eliminated each time.

Concepts Checklist

Exam Tips & Common Mistakes

Trap 1 Don't confuse "weak acid" with "dilute acid." They describe completely different things — degree of ionisation vs. concentration.
Trap 2 In alkaline hydrolysis of an ester, the direct product is the carboxylate salt, NOT the carboxylic acid. Examiners will catch you if you write "propanoic acid" instead of "sodium propanoate" for a straight NaOH hydrolysis with no acidification step mentioned.
Trap 3 Forgetting the "2" in front of ammonia/amine when writing amide-formation equations from acyl chlorides — remember, one molecule forms the amide, a second neutralises the HCl.
Trap 4 Mixing up ester naming order. The alcohol-derived part comes first, the acid-derived part (ending in "-oate") comes second. "Ethyl propanoate" = from ethanol + propanoic acid, not the other way round.
Trap 5 LiAlH₄ must be used in dry ether, never in water — it reacts violently/explosively with water. Water is only added at the very end to safely destroy the excess reagent.
What examiners actually look for
  • Correct state symbols and balanced equations (including the "n" in polymer equations).
  • Precise observations: "orange to green," "purple to colourless," "steamy fumes," "effervescence."
  • Using "reversible/equilibrium" vs "irreversible/goes to completion" as the exact justification language for acid vs alkaline ester hydrolysis — this phrasing is often exactly what the mark scheme wants.
  • Correctly identifying which functional groups a monomer needs to form a condensation polymer (2 of each group, or one of each per monomer).
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Also in the full note
  • 1. Carboxylic Acids — Structure & Physical Properties
  • 4. Acyl Chlorides & Esters
  • 5. Acid & Alkaline Hydrolysis of Esters
  • Exam Tips & Common Mistakes
  • Route 1: Oxidation of primary alcohols & aldehydes
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