O Level · International Mathematics 0607

Vectors

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Cambridge IGCSE · International Maths Extended

Vectors

A vector is just an instruction for how far to move and in which direction — and once you can add, subtract, scale, and measure the length of those instructions, this whole chapter is yours.

Revision Guide · Column Vectors · Vector Diagrams · Magnitude

Summary — What This Chapter Covers

  • Column vectors describe a movement from one point to another — a top number for left/right, a bottom number for up/down.
  • You can add and subtract column vectors by combining the top numbers together and the bottom numbers together.
  • You can multiply a vector by a scalar (an ordinary number) — this stretches, shrinks, or flips the vector.
  • Vectors can be drawn as arrows on a diagram — the length shows magnitude, the arrowhead shows direction.
  • A vector from point to point is written AB→, and it points the way to BA→ — same length, reversed direction.
  • The magnitude (length) of a vector is found using Pythagoras' theorem on its two components.
  • Multiplying by a negative scalar reverses the direction of a vector as well as changing its length.

1. Introduction to Column Vectors

Imagine you're giving someone directions across a grid — not "turn left at the shop," but pure movement: That's exactly what a column vector is: a set of travel instructions written as a little vertical pair of numbers.

What a column vector means
( 6, 3 )  →  means "6 units to the right, and 3 units up"
The top number is the horizontal (x) movement. The bottom number is the vertical (y) movement. A negative sign flips the direction — negative top = left, negative bottom = down.

Column vectors are also called translation vectors, because they describe exactly the same thing as a translation in geometry — a slide, with no rotation and no resizing. If you've done translations before, you already half-know this topic.

x ← top number → movement in x-direction (+ right, − left) Vector = ( x ) ( y ) ← bottom number → movement in y-direction (+ up, − down)
Quick way to remember it
Think "along the corridor, then up the stairs" — top number first (sideways), bottom number second (up/down). It's the same order as coordinates (x, y), just written vertically instead of with a comma.
Adding and Subtracting Column Vectors

This is the easiest operation in the whole chapter, because there's no trick — you just deal with the top numbers together, and the bottom numbers together, completely separately. Think of it like two separate number lines running in parallel: one for "sideways total," one for "up/down total."

Addition & Subtraction Rule
( a, b ) + ( c, d ) = ( a + c , b + d )
( a, b ) − ( c, d ) = ( a − c , b − d )
Add/subtract tops with tops, and bottoms with bottoms. Never mix a top number with a bottom number.

For example:

( 5 ) ( 3 ) ( 5+3 ) ( 8 ) ( 2 ) + (−1 ) = ( 2+(−1)) = ( 1 ) ( 5 ) ( 3 ) ( 5−3 ) ( 2 ) ( 2 ) − (−1 ) = ( 2−(−1)) = ( 3 )
Common mistake: students sometimes forget that subtracting a negative number means adding. In the subtraction example above, 2 − (−1) is 2 + 1 = 3, not 1. Always rewrite double negatives before calculating.
Practice Question 1
Work out ( 4, −7 ) + ( −9, 2 ).
Practice Question 2
Work out ( 6, 1 ) − ( −2, 5 ).
Multiplying a Vector by a Scalar

A scalar is just an ordinary number — it has size but no direction (that's the whole point of the name: it "scales" things up or down, it doesn't point anywhere). When you multiply a vector by a scalar, you multiply components by that number.

Scalar Multiplication Rule
k × ( x, y ) = ( kx, ky )
Multiply the top number by k, and multiply the bottom number by k. Both parts get scaled by the same amount.
3 × ( 2 ) = ( 3×2 ) = ( 6 ) (−1) = ( 3×(−1)) = (−3)

Where this gets slightly trickier — and where exam questions like to test you — is when an expression mixes scalar multiplication addition/subtraction in one line. The fix is simply order of operations: multiply first, then add or subtract.

Simplifying a Vector Expression — 2 Steps
Step 1: Multiply each vector by the scalar in front of it.
Step 2: Add or subtract the resulting column vectors (top with top, bottom with bottom).
2( 5 ) + 5( 3 ) ( 2 ) (−1) Step 1: ( 2×5 ) + ( 5×3 ) = ( 10 ) + ( 15 ) ( 2×2 ) ( 5×(−1)) ( 4 ) (−5 ) Step 2: ( 10+15 ) = ( 25 ) ( 4+(−5) ) (−1 )
Worked Example
Given a = ( p, 3 ) and b = ( −2, 1 ), and 2a + 3b = ( 4, q ), find p and q.

Step 1 — write as one vector: 2a = (2p, 6) and 3b = (−6, 3), so 2a + 3b = (2p − 6, 9).
Step 2 — this equals (4, q): so (2p − 6, 9) = (4, q).
Step 3 — match components: top numbers: 2p − 6 = 4 → 2p = 10 → p = 5. Bottom numbers: 9 = q → q = 9.

This "match the top with the top, and the bottom with the bottom" idea — two equal vectors must have equal components — is one of the most useful exam tricks in this whole topic.
Practice Question 3
Simplify 3( −1, 4 ) − 2( 2, −3 ) into a single column vector.
Practice Question 4
c = ( t, −4 ) and d = ( 3, 2 ). Given that 4cd = ( 5, k ), find t and k.

2. Representing Vectors as Diagrams

A vector has two properties: a magnitude (its size — how far it goes) and a direction (which way it's pointing). To show both on a diagram, you draw a straight line whose represents the magnitude, and an at the end to show which way it's pointing. Without the arrow, it's just a line segment — it's the arrow that turns it into a vector.

⤴ / / ← the line's length = magnitude / • ← the arrowhead = direction (no arrow here — this end is just the "tail" of the vector)
Notation you MUST get right
Vectors are written in bold when typed (e.g. a), to show they're a vector and not an ordinary number. When you're handwriting in an exam, you can't easily write in bold — so you underline the letter instead: a. Good news: examiners will not take marks off if you forget to underline — but it's still good habit, because it keeps your own working clear.

If a vector starts at point and ends at point , we write it as AB→ (an arrow drawn over "AB", pointing right). The order of the letters matters enormously here:

Direction depends on letter order
AB→ points from A toward B.   BA→ points from B toward A.
AB→ and BA→ have exactly the same length, but point in completely opposite directions. In fact, BA→ = −AB→. Reading the letters left-to-right tells you "start point → end point," just like reading a sentence.
Common mistake: writing AB→ when you actually mean BA→ (or vice versa) — this silently flips the sign of every component and the direction of the arrow. Always double-check which letter comes in the vector name before you commit to a direction on your diagram.
Drawing a Vector on a Grid

You can draw a vector on a grid — its position doesn't matter, only its length and direction do (this is a really important idea: two vectors with the same components represent the "same" vector even if drawn in totally different places on the page).

How to draw a = ( 3, 4 )
1. Pick any starting point and mark a dot.
2. Count 3 units right and 4 units up from that dot, and mark a second dot.
3. Draw a straight line connecting the two dots.
4. Add an arrowhead pointing toward the dot (the one you counted to).

Watch out for negative numbers and zeros — they're where students most often draw the wrong picture:

b = ( 2, −4 ) → goes 2 right AND 4 down (the minus flips vertical direction) c = ( 2, 0 ) → goes 2 right, and does NOT move up or down at all — a flat horizontal arrow
Practice Question 5
Describe in words how you would draw the vector d = ( −5, −2 ) starting from the origin.
Multiplying a Vector by a Scalar — Visually

You already know the arithmetic rule (multiply both components). Here's what it actually like on a diagram, which is where a lot of understanding really clicks into place.

Positive scalar
Multiplying by a positive scalar keeps the direction exactly the same — the arrow points the same way — but stretches (if the scalar > 1) or shrinks (if 0 < scalar < 1) the length by that factor.
a = ( 4, −2 ) 2a = ( 8, −4 ) → same direction as a, but DOUBLE the length ½a = ( 2, −1 ) → same direction as a, but HALF the length
Negative scalar
Multiplying by a negative scalar reverses the direction (the arrow flips 180°) AND scales the length by the size of the number (ignoring its sign).
a = ( 4, −2 ) −a = (−4, 2) → opposite direction to a, SAME length −2a = (−8, 4) → opposite direction to a, DOUBLE the length
The one-sentence version
The sign of the scalar controls direction (positive = same way, negative = flipped), and the size of the scalar controls length (bigger number = longer arrow, fraction = shorter arrow).
Adding and Subtracting Vectors — Visually (Nose-to-Tail)

This is often called the nose-to-tail method, and it's the visual version of vector addition. Picture walking along one vector, then immediately continuing your walk along the second vector from wherever the first one left you. The "total journey" — from your very first starting point to your very last ending point — is the vector a + b.

Drawing a + b
1. Draw vector a first.
2. Starting exactly where a ended (nose-to-tail — the "nose"/arrowhead of a meets the "tail" of b), draw vector b.
3. Draw a new line straight from the very start of a to the very end of b. That line, with an arrowhead at the end, IS the vector a + b.

Subtraction works the same way, but remember that ab is really just a + (−b) — so you draw a as normal, then draw b reversed (i.e. −b, pointing the opposite way) starting from the end of a.

Drawing a − b
1. Draw vector a first.
2. Starting where a ended, draw −b (same length as b, but pointing the opposite way).
3. Draw a new line from the start of a to the end of −b. That's ab.
Worked Example
Points A(−4, 2), B(2, 4), and C(3, −4). Find AB→, AC→, and CB→ as column vectors.

The rule for any vector from point P(x₁, y₁) to point Q(x₂, y₂) is PQ→ = (x₂ − x₁, y₂ − y₁) — end point minus start point, top with top, bottom with bottom.

AB→ = (2 − (−4), 4 − 2) = (6, 2) — 6 right and 2 up.
AC→ = (3 − (−4), −4 − 2) = (7, −6) — 7 right and 6 down.
CB→ = (2 − 3, 4 − (−4)) = (−1, 8) — 1 left and 8 up.

Bonus insight: notice that AB→ + BC→ + CA→ always equals (0, 0) for any three points — because it describes a journey that starts at A, wanders to B, then C, then returns all the way back to A. Since you end up exactly where you started, the total displacement is nothing at all — a closed loop always sums to the zero vector. This is a classic "explain why" exam question, and no calculation is needed to answer it — just describe the journey!
Practice Question 6
Points P(1, 5) and Q(−3, 2). Find the column vector PQ→.
Practice Question 7
a = ( 3, 1 ) and b = ( −2, 5 ). Write ab as a single column vector, and describe what this vector would look like drawn on a diagram.

3. Magnitude of a Vector

The magnitude of a vector is simply its — how far you'd actually travel if you walked along it, measured as a straight-line distance. It's also called the modulus of the vector (same idea, fancier name — you'll see both used interchangeably in exams). Two crucial things to remember about magnitude:

  • It's always positive (or zero) — length can't be negative, even if the vector's components are negative.
  • It ignores direction completely — the magnitude only cares about "how far," not "which way." That's why |AB→| = |BA→| — reversing a vector doesn't change how long it is.
Magnitude Formula (Pythagoras' Theorem)
If a = ( x, y ), then |a| = √(x² + y²)
The magnitude of AB→ is written |AB→|, and the magnitude of a is written |a| — vertical bars around the vector, just like absolute value bars around a number.

Why does this work? Picture the vector as the diagonal (hypotenuse) of a right-angled triangle: the horizontal component (x) is one shorter side, the vertical component (y) is the other shorter side, and the vector itself is the hypotenuse connecting them. Pythagoras' theorem — the same one you use for right-angled triangles everywhere else in maths — gives you the length of that hypotenuse directly from the two shorter sides.

Q ╱│ ╱ │ y (vertical side) vector ╱ │ ╱ │ P ─────── (right angle here) x (horizontal side) Magnitude of the vector = length PQ = hypotenuse = √(x² + y²)
Exam Tip
If there's no diagram given in the question, sketch one yourself. Turning an abstract column vector into a little right-angled triangle on your working paper makes Pythagoras' theorem obvious to apply — and it helps you catch sign errors, because you can visually check whether your answer's direction "looks right."
Worked Example
Points A(−3, 5) and B(7, 1).

(a) Find AB→ as a column vector.
AB→ = (end − start) = (7 − (−3), 1 − 5) = (10, −4).

(b) Find the magnitude of AB→.
|AB→| = √(10² + (−4)²) = √(100 + 16) = √116 = 2√29 (leave in surd form unless told to give a decimal).

(c) Briefly explain why |BA→| = |AB→|.
Magnitude measures a vector's only — direction is irrelevant to length. AB→ and BA→ cover exactly the same physical distance between the same two points, just described in opposite directions, so their magnitudes must be identical.

(d) Vector CD→ has three times the magnitude of AB→. Write down a possible column vector for CD→.
Multiplying AB→'s components by 3 (or −3) multiplies its length by exactly 3, while keeping (or reversing) its direction: 3 × (10, −4) = (30, −12), or equally valid, −3 × (10, −4) = (−30, 12). Either answer is correct because the question only fixed the magnitude, not the direction.
Common mistake: forgetting to square the negative components properly. Remember (−4)² = +16, not −16 — a squared number is always positive, regardless of the sign you started with. This trips up a huge number of students under exam pressure.
Practice Question 8
Find the magnitude of the vector v = ( 6, 8 ). Give an exact answer.
Practice Question 9
Points M(2, −1) and N(−4, 7). Find |MN→|, giving your answer in simplified surd form if necessary.

What to Memorise

FormulasNotationKey Terms
Term / FormulaWhat it means
( x, y )Column vector: x = horizontal movement (+ right, − left), y = vertical movement (+ up, − down)
(a,b) + (c,d)= (a+c, b+d) — add tops together, add bottoms together
(a,b) − (c,d)= (a−c, b−d) — subtract tops together, subtract bottoms together
k(x, y)= (kx, ky) — scalar multiplication: multiply both components by k
ScalarAn ordinary number with size but no direction (used to scale a vector)
AB→Vector starting at A, ending at B. AB→ = (Bx − Ax, By − Ay)
BA→ = −AB→Same length as AB→, but points the exact opposite direction
Magnitude / ModulusThe length of a vector — always positive, direction-independent
|a| = √(x² + y²)Pythagoras' theorem applied to the vector's components
Nose-to-tailMethod for drawing a + b: draw a, then draw b starting where a ended
Negative scalarReverses vector direction AND scales the length by the number's size
Closed loop ruleAB→ + BC→ + CA→ = (0,0) — any journey that returns to its start sums to zero

Concepts Checklist

Exam Tips

Trap 1 — Sign errors in subtraction. "5 − (−1)" is a favourite way examiners sneak in an easy mark loss. Always rewrite double negatives as addition before you calculate: 5 − (−1) = 5 + 1 = 6.
Trap 2 — Mixing up AB→ and BA→. The letter order tells you start point → end point. If a question swaps the order compared to what you expect, your whole answer flips sign. Always calculate as (end coordinates) − (start coordinates).
Trap 3 — Forgetting a squared negative is positive. When applying Pythagoras' theorem to find magnitude, (−6)² = 36, never −36. This is one of the most common silly mistakes in the whole IGCSE vectors topic.
Trap 4 — "Explain why" questions. When asked to explain something like why AB→ + BC→ + CA→ = (0,0), examiners want a explanation (start and end at the same place → zero total displacement), not a full column-vector calculation. Marks are awarded for the reasoning, not the arithmetic.
Trap 5 — Leaving surds unsimplified. If a magnitude calculation gives you √116, check whether it simplifies (√116 = √(4×29) = 2√29). Examiners often want the simplified surd form unless a decimal is explicitly requested.
What examiners are actually looking for
Clear, labelled column vector notation (brackets, correctly stacked numbers), one clean line of working showing tops-with-tops and bottoms-with-bottoms, and — for magnitude questions — visible use of Pythagoras' theorem (x² + y² under a square root sign) rather than a magnitude number appearing "from nowhere." Show every step; method marks are generous in this topic.
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