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Centres of Mass

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  Edexcel IAL Mechanics 2 (WME02)

Centres of Mass

The big idea: The centre of mass is a weighted average of positions: multiply each mass by its position, add, and divide by the total mass.

Summary — What This Chapter Covers
  • Particles: x̄ = Σmx / Σm and ȳ = Σmy / Σm.
  • Composite laminas: treat each simple shape as a particle at its own centre; subtract removed parts.
  • A freely suspended body hangs with its centre of mass vertically below the point of suspension.
1. Centre of Mass of Particles
Particles

Weighted averages

Tabulate mass, x and y for every particle, then take the weighted averages.

Worked Example

Particles of mass 2 kg, 3 kg and 5 kg are at (1, 3), (4, −1) and (−2, 2). Find their centre of mass.

2. Centre of Mass of Uniform Plane Figures
Laminas

Composite shapes

For a uniform lamina, mass is proportional to area. Standard results (triangle at the mean of its vertices, sector, arc) are in the formula book. A hole is a negative mass.

Worked Example

A rectangle 0 ≤ x ≤ 6, 0 ≤ y ≤ 4 has the square 4 ≤ x ≤ 6, 2 ≤ y ≤ 4 removed. Find the centre of mass.

3. Equilibrium of Laminas
Suspension

Hanging and tilting

Suspended from a point P, the line PG is vertical. The angle a given edge makes with the vertical comes from the right-angled triangle formed by G and that edge. A body on an inclined plane is about to topple when the line of action of its weight passes through the lowest corner.

Practice Question
Memorise
Particles

x̄ = Σmx/Σm

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