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Quadratics

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 1

Quadratics

The big idea: Every quadratic can be rewritten as a(x + p)2 + q. That one form tells you the vertex, the number of roots and the solution, and the discriminant b2 − 4ac is its shortcut.

Summary — What This Chapter Covers
  • Completing the square: ax2 + bx + c = a(x + p)2 + q, with vertex (−p, q).
  • The discriminant b2 − 4ac decides the number of real roots: two, one repeated root, or none.
  • Solve quadratic equations by factorising, completing the square or the formula.
  • Solve quadratic inequalities by finding the roots, then sketching the parabola.
  • Simultaneous equations (one linear, one quadratic): substitute the linear one into the quadratic.
  • Equations that are quadratic in x2, √x, tan x and so on: substitute u for that function.
1. Completing the Square and the Discriminant
Completed square form

a(x + p)2 + q

Take out the coefficient of x2 from the first two terms, halve the coefficient of x inside the bracket, and correct for the extra constant. Because (x + p)2 ≥ 0, the completed square form shows the least (or greatest) value at once: the vertex of y = a(x + p)2 + q is (−p, q), a minimum if a > 0 and a maximum if a < 0.

The discriminant of ax2 + bx + c is b2 − 4ac. It is the part of the quadratic formula under the square root, so its sign tells you how many real roots the equation ax2 + bx + c = 0 has.

Discriminant b2 − 4ac > 0: two distinct real roots  ·  b2 − 4ac = 0: one repeated root  ·  b2 − 4ac < 0: no real roots
Worked Example

Express 2x2 − 12x + 7 in the form a(x + b)2 + c and state the coordinates of the vertex of y = 2x2 − 12x + 7.

Practice Question 1

Find the values of k for which x2 + kx + 9 = 0 has a repeated root.

Practice Question 2

Find the set of values of k for which 2x2 + kx + 8 = 0 has no real roots.

2. Quadratic Equations and Inequalities
Solving

Equations by three methods, inequalities by a sketch

Factorise when you can see the factors quickly. Otherwise use the formula, or complete the square. For an inequality, solve the equation first to find the critical values, then sketch the parabola: for a positive x2 coefficient the curve is below the axis between the roots and above it outside them.

Quadratic formula x = [−b ± √(b2 − 4ac)] / (2a)
Worked Example

Solve 2x2 − 5x − 3 < 0.

Practice Question 1

Solve x2 + 4x − 1 = 0, giving your answers in exact form.

Practice Question 2

Solve x2 − x − 6 ≥ 0.

3. Simultaneous Equations and Disguised Quadratics
Substitution

Reduce everything to one quadratic

linear

An equation like x4 − 5x2 + 4 = 0 is a quadratic in x2. Let u = x2 (or u = √x, u = tan x, …), solve for u, then go back to x and reject impossible values (for example √x cannot be negative).

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