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Trigonometry

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 2

Trigonometry

The big idea: Six trig functions, a handful of identities, and one idea: choose the identity that turns the equation into a single trig function of a single angle.

Summary — What This Chapter Covers
  • sec θ = 1/cos θ, cosec θ = 1/sin θ, cot θ = 1/tan θ = cos θ/sin θ.
  • sec2θ ≡ 1 + tan2θ and cosec2θ ≡ 1 + cot2θ.
  • Compound angle formulae for sin(A ± B), cos(A ± B) and tan(A ± B).
  • Double angle formulae for sin 2A, cos 2A (three forms) and tan 2A.
  • a sin θ + b cos θ can be written as R sin(θ ± α) or R cos(θ ± α), with R = √(a2 + b2).
1. Secant, Cosecant and Cotangent
Reciprocal functions

The other three functions

sec, cosec and cot are reciprocals, so they are undefined wherever cos, sin or tan is zero; their graphs have vertical asymptotes there. sec θ and cosec θ are never between −1 and 1. Divide sin2θ + cos2θ ≡ 1 by cos2θ or sin2θ to get the two new identities.

Identities sec2θ ≡ 1 + tan2θ  ·  cosec2θ ≡ 1 + cot2θ
Worked Example

Solve 2 sec2θ − 5 tan θ = 0 for 0° ≤ θ ≤ 360°.

Practice Question 1

Solve tan θ + cot θ = 4 for 0° < θ < 180°.

Practice Question 2

Find the exact values of sec(π/3), cosec(5π/6) and cot(3π/4).

2. Compound and Double Angle Formulae and R cos(θ − α)
Identities

Expanding, doubling and combining

The compound angle formulae give exact values for angles like 15° and 75°, and simplify expressions such as cos(x − 30°). Put A = B to get the double angle formulae. Choose the form of cos 2A that leaves one trig function in the equation.

To write a cos θ + b sin θ as R cos(θ − α), expand R cos(θ − α) = R cos θ cos α + R sin θ sin α and compare: R cos α = a, R sin α = b. Then R = √(a2 + b2) and tan α = b/a. This form gives the greatest and least values (±R) and turns the equation into a single cosine.

Compound angles sin(A ± B) = sin A cos B ± cos A sin B
cos(A ± B) = cos A cos B ∓ sin A sin B
tan(A ± B) = (tan A ± tan B)/(1 ∓ tan A tan B)
Double angles sin 2A = 2 sin A cos A  ·  cos 2A = cos2A − sin2A = 2cos2A − 1 = 1 − 2sin2A  ·  tan 2A = 2 tan A/(1 − tan2A)
Worked Example

Express 3 cos θ + 4 sin θ in the form R cos(θ − α), with R > 0 and 0° < α < 90°. Hence solve 3 cos θ + 4 sin θ = 2 for 0° ≤ θ ≤ 360°.

Practice Question 1

Find the exact value of sin 75°.

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