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Differentiation

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 2

Differentiation

The big idea: Add five new standard derivatives to xn, combine them with the product, quotient and chain rules, and you can differentiate almost anything, including curves that are not written as y = f(x).

Summary — What This Chapter Covers
  • d/dx ex = ex, d/dx ln x = 1/x, d/dx sin x = cos x, d/dx cos x = −sin x, d/dx tan x = sec2x.
  • With the chain rule: d/dx ekx = kekx, d/dx ln(ax + b) = a/(ax + b), d/dx sin kx = k cos kx.
  • Product rule: (uv)′ = u′v + uv′. Quotient rule: (u/v)′ = (u′v − uv′)/v2.
  • Parametric: dy/dx = (dy/dt) ÷ (dx/dt).
  • Implicit: differentiate each term with respect to x, writing d/dx(yn) = nyn−1 dy/dx.
1. Derivatives of ex, ln x and Trigonometric Functions
Standard derivatives

Five new results

Angles must be in radians for the trig derivatives. Each result extends with the chain rule: differentiate the outer function and multiply by the derivative of the inside.

Standard derivatives ex → ex  ·  ln x → 1/x  ·  sin x → cos x  ·  cos x → −sin x  ·  tan x → sec2x
ef(x) → f′(x)ef(x)  ·  ln f(x) → f′(x)/f(x)
Worked Example

Differentiate y = e3x + ln(2x − 1) + sin 4x.

Practice Question 1

Differentiate y = tan 2x − 3 cos(x/2).

Practice Question 2

Find the gradient of y = ln(x2 + 1) at x = 1.

2. Product, Quotient and Chain Rules
Combining rules

Products, quotients and composites

Identify the structure first: a product of two functions, a quotient, or a function of a function. Many questions combine them, for example x e−2x needs the product rule and the chain rule. To find stationary points, set the derivative to zero; eanything is never zero, so factor it out.

Rules d/dx(uv) = u dv/dx + v du/dx  ·  d/dx(u/v) = (v du/dx − u dv/dx)/v2
Worked Example

Differentiate (a) x2 ln x, (b) (2x − 4)/(3x + 2).

Worked Example

Find the exact coordinates of the stationary point of y = x e−2x.

Practice Question

Differentiate y = x e−x2.

3. Parametric and Implicit Differentiation
Parametric and implicit

When y is not given as f(x)

Parametric: x and y are both given in terms of a parameter t. Find dx/dt and dy/dt and divide. To find a tangent, find the point and the gradient at the same value of t.

Implicit: differentiate every term with respect to x. A term in y picks up a factor dy/dx by the chain rule, and a term like xy needs the product rule. Then collect the dy/dx terms and factorise.

Methods 2
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