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Trigonometry

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 3

Trigonometry

The big idea: Three reciprocal functions and a handful of identities let you rewrite any trig expression into one that a single equation can solve. The skill is choosing the identity that leaves only one function of one angle.

Summary — What This Chapter Covers
  • sec θ = 1/cos θ, cosec θ = 1/sin θ, cot θ = 1/tan θ = cos θ/sin θ.
  • sec2θ ≡ 1 + tan2θ and cosec2θ ≡ 1 + cot2θ.
  • Compound angles: sin(A ± B), cos(A ± B), tan(A ± B) — in the formula list, but you must use them fluently.
  • Double angles: sin 2A = 2 sin A cos A; cos 2A = cos2A − sin2A = 2cos2A − 1 = 1 − 2sin2A; tan 2A = 2tan A/(1 − tan2A).
  • a sin θ + b cos θ can be written as R sin(θ ± α) or R cos(θ ± α), with R = √(a2 + b2).
1. Secant, Cosecant and Cotangent
Reciprocal functions

Graphs, identities and equations

The graph of y = sec θ has vertical asymptotes wherever cos θ = 0 (θ = 90°, 270°, …), and |sec θ| ≥ 1 everywhere. y = cosec θ has asymptotes where sin θ = 0 (0°, 180°, …), also with |cosec θ| ≥ 1. y = cot θ has asymptotes where tan θ = 0 and crosses the axis where tan θ has its asymptotes.

Divide sin2θ + cos2θ ≡ 1 by cos2θ or by sin2θ to get the two new Pythagorean identities. Use them to turn an equation into a quadratic in one function.

Identities sec2θ ≡ 1 + tan2θ     cosec2θ ≡ 1 + cot2θ
Worked Example

Solve 2tan2θ + sec θ = 1 for 0° ≤ θ ≤ 360°.

Practice Question

Solve tan θ + cot θ = 4 for 0° < θ < 360°.

2. Compound and Double Angle Formulae and R cos(θ − α)
Identities

Expanding, collapsing and the R form

Compound-angle formulae give exact values such as sin 15° or tan 75°, and turn expressions like cos(x − 30°) into terms in sin x and cos x. Double-angle formulae replace a 2θ with θ; choose the version of cos 2A that leaves only one function in the equation.

To write a sin θ + b cos θ as a single wave, expand the target form and compare coefficients. Then the maximum and minimum are ±R, and an equation a sin θ + b cos θ = c becomes one equation in (θ ± α).

Formulae sin(A ± B) = sin A cos B ± cos A sin B    cos(A ± B) = cos A cos B ∓ sin A sin B
tan(A ± B) = (tan A ± tan B)/(1 ∓ tan A tan B)
R form a cos θ + b sin θ = R cos(θ − α), where R = √(a2 + b2), R cos α = a, R sin α = b, tan α = b/a
Worked Example 1

Find the exact value of tan 75°.

Worked Example 2

Express 3cos θ + 4sin θ in the form R cos(θ − α), where R > 0 and 0° < α < 90°. Hence solve 3cos θ + 4sin θ = 2 for 0° < θ < 360°.

Practice Question 1

Solve cos 2θ + 3sin θ = 2 for 0° ≤ θ ≤ 360°.

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