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Differentiation

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 3

Differentiation

The big idea: Learn six standard derivatives and three rules (chain, product, quotient), and you can differentiate any function in this paper, including curves given parametrically or implicitly.

Summary — What This Chapter Covers
  • d/dx(ex) = ex, d/dx(ln x) = 1/x, d/dx(sin x) = cos x, d/dx(cos x) = −sin x, d/dx(tan x) = sec2x, d/dx(tan−1x) = 1/(1 + x2).
  • x must be in radians for the trig derivatives.
  • Chain rule for composites, product rule for uv, quotient rule for u/v.
  • Parametric: dy/dx = (dy/dt) ÷ (dx/dt).
  • Implicit: differentiate every term with respect to x; a term in y picks up a factor dy/dx.
1. Derivatives of ex, ln x and Trigonometric Functions
Standard results

The six you must know

With the chain rule, each standard result extends to a linear (or any) inner function: d/dx ef(x) = f′(x)ef(x), d/dx ln f(x) = f′(x)/f(x), d/dx sin f(x) = f′(x)cos f(x). Derivatives of sin−1x and cos−1x are not required.

Standard derivatives eax + b → aeax + b    ln(ax + b) → a/(ax + b)    sin ax → a cos ax    cos ax → −a sin ax
tan ax → a sec2ax    tan−1x → 1/(1 + x2)
Worked Example

Differentiate y = e3x + ln(2x) + sin 4x + tan−1(2x).

Simplify logs first
ln(2x) = ln 2 + ln x, so its derivative is just 1/x. Likewise ln(x3) = 3 ln x. Splitting the log before differentiating often saves a quotient rule.
2. Product, Quotient and Chain Rules
Rules

Building derivatives of combined functions

Identify the structure first: a function of a function (chain), a product of two functions (product), or one function over another (quotient). Many questions then ask for a stationary point: set dy/dx = 0. An exponential factor such as e−2x is never zero, so it can be cancelled.

Rules Chain: dy/dx = (dy/du)(du/dx)    Product: (uv)′ = u′v + uv′    Quotient: (u/v)′ = (u′v − uv′)/v2
Worked Example 1

Differentiate (a) x2 ln x   (b) xe1 − x2   (c) (2x − 4)/(3x + 2).

Worked Example 2

Find the exact coordinates of the stationary point on y = xe−2x.

Practice Question

Find the x-coordinate of the stationary point on y = (ln x)/x and state the exact value of y there.

3. Parametric and Implicit Differentiation
Parametric & implicit

Gradients without y = f(x)

Parametric: when x and y are both given in terms of t, find dx/dt and dy/dt and divide. To find a tangent or normal at a point, find the value of t first.

Implicit: differentiate both sides with respect to x. d/dx(y2) = 2y dy/dx, and a product such as xy needs the product rule: d/dx(xy) = y + x dy/dx. Then collect the dy/dx terms.

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