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Newton's Laws of Motion

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  Cambridge International AS & A Level Mathematics 9709 — Mechanics

Newton's Laws of Motion

The big idea: Resultant force = mass × acceleration: write F = ma for each particle (or the whole system) in the direction of motion, and the problem solves itself.

Summary — What This Chapter Covers
  • Newton's first law: no resultant force means constant velocity (including rest).
  • Newton's second law: resultant force = ma, with the acceleration in the direction of the resultant.
  • Weight W = mg with g = 10 m s−2.
  • Connected particles: write F = ma for each particle; a light inextensible string has the same tension throughout and both ends share the same acceleration.
  • On a rough slope the acceleration up the slope differs from the acceleration down it, because friction changes direction.
1. Newton's Second Law
F = ma

Resultant force in the direction of the acceleration

Draw the force diagram, decide the direction of the acceleration and write (sum of forces in that direction) = ma. Perpendicular to the motion, the forces balance (no acceleration there). Combine with suvat when you need distances or times — this is constant acceleration because the forces are constant.

Resistances other than friction (such as air resistance) are only included when the question mentions them. Vertical motion includes lifts: the reaction from the floor is the person's "apparent weight".

Newton's second law Fresultant = ma    W = mg (g = 10 m s−2)
Worked Example

A car of mass 1200 kg has a driving force of 3000 N and experiences a resistance of 600 N. Find its acceleration and the time taken to reach 24 m s−1 from rest.

Practice Question 1

A man of mass 70 kg stands in a lift that is accelerating upwards at 1.5 m s−2. Find the reaction from the floor.

2. Connected Particles and Pulleys
Connected

One equation per particle

For particles joined by a light inextensible string, the tension is the same at both ends and both particles have the same magnitude of acceleration. Over a smooth pulley the tension is unchanged. Write F = ma separately for each particle in its own direction of motion, then add or solve simultaneously.

For a car towing a trailer, the tow-bar or rope carries a tension T when accelerating; a rigid tow-bar can also push, giving a thrust when braking. Treating the whole system as one body gives the acceleration quickly (internal forces cancel); then use one part to find T.

Worked Example 1

Particles A (5 kg) and B (3 kg) hang on either side of a smooth fixed pulley, connected by a light inextensible string, and are released from rest. Find the acceleration and the tension.

Worked Example 2

A block of mass 4 kg on a rough horizontal table (μ = 0.25) is joined by a string over a smooth pulley at the edge to a particle of mass 2 kg hanging freely. Find the acceleration and the tension.

Practice Question 2

A car of mass 1000 kg tows a trailer of mass 400 kg with a light rigid tow-bar. The driving force is 2500 N; the resistances are 300 N on the car and 100 N on the trailer. Find the acceleration and the tension in the tow-bar.

3. Motion on Inclined Planes
Slopes
Memorise
Second law
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  • Friction always opposes the motion
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