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The Normal Distribution

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  Cambridge International AS & A Level Mathematics 9709 — Probability & Statistics 1

The Normal Distribution

The big idea: Every normal distribution is the standard normal stretched and shifted, so standardise with z = (x − μ)/σ and the table does the rest.

Summary — What This Chapter Covers
  • X ~ N(μ, σ2) is a continuous, symmetrical, bell-shaped distribution — note the second parameter is the variance.
  • Standardise: Z = (X − μ)/σ, with Z ~ N(0, 1); show this working in full.
  • Use the table for Φ(z) and symmetry: Φ(−z) = 1 − Φ(z).
  • Given a probability, use the inverse table (critical values) to find z, then form equations in μ and σ.
  • Normal approximation to B(n, p) when np > 5 and nq > 5: use N(np, npq) with a continuity correction.
1. Normal Distribution Probabilities
Probabilities

Standardise, sketch, look up

Sketch the curve, shade the region you want, standardise the boundary values and look up Φ(z) = P(Z < z). For areas to the right use 1 − Φ(z); for negative z use symmetry. For a continuous variable, P(X < a) = P(X ≤ a).

Standardising Z = (X − μ)/σ    P(X < x) = Φ((x − μ)/σ)    Φ(−z) = 1 − Φ(z)
Worked Example

X ~ N(50, 16). Find P(X > 56) and P(46 < X < 55).

Practice Question 1

X ~ N(50, 16). Find a such that P(X < a) = 0.9.

2. Finding μ and σ
Unknown parameters

Probability → z → equation

If a probability is given, read the z-value from the inverse table (watch the sign: a value below the mean has negative z). Each probability gives one equation (x − μ)/σ = z; with two unknowns you need two equations, solved simultaneously.

Worked Example

X ~ N(μ, σ2). P(X < 30) = 0.2 and P(X > 50) = 0.1. Find μ and σ.

Practice Question 2

X ~ N(μ, 25) and P(X > 40) = 0.0228. Find μ.

3. Normal Approximation to the Binomial
Approximation

Continuity correction

If X ~ B(n, p) with n large enough that np > 5 and nq > 5 (q = 1 − p), X is approximately N(np, npq). The binomial is discrete, so each integer r is represented by the interval r − 0.5 to r + 0.5: this is the continuity correction.

Continuity corrections P(X ≥ 30) → P(Y > 29.5)    P(X > 30) → P(Y > 30.5)    P(X ≤ 30) → P(Y < 30.5)    P(X = 30) → P(29.5 < Y < 30.5)
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