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The Poisson Distribution

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  Cambridge International AS & A Level Mathematics 9709 — Probability & Statistics 2

The Poisson Distribution

The big idea: The Poisson distribution counts random events in a fixed interval; its one parameter λ is both the mean and the variance, and it scales with the length of the interval.

Summary — What This Chapter Covers
  • X ~ Po(λ): P(X = r) = e−λλr/r!, r = 0, 1, 2, …
  • Mean = variance = λ.
  • Model conditions: events occur singly, independently, at random, at a constant average rate.
  • Change the interval by scaling λ in proportion.
  • Po(np) approximates B(n, p) when n > 50 and np < 5.
  • N(λ, λ) approximates Po(λ) when λ > 15, with a continuity correction.
1. Poisson Probabilities, Mean and Variance
Po(λ)

Random events in an interval

Use the Poisson distribution for the number of events in a fixed interval of time or space when the events occur randomly, independently, singly and at a constant average rate. Explain suitability in context: "the calls arrive independently and at a constant average rate". A quick check from data: if the sample mean and variance are roughly equal, Poisson is plausible.

If the rate is 3 per hour, the number in half an hour is Po(1.5) and the number in 4 hours is Po(12).

Poisson formula P(X = r) = e−λ λr / r!    E(X) = Var(X) = λ
Worked Example

Calls arrive at a switchboard at random at an average rate of 3 per hour. Find the probability of exactly 2 calls in an hour, of at least 2 calls in an hour, and of at most 1 call in 30 minutes.

2. Approximations Using the Poisson and Normal Distributions
Approximations

When and how

Binomial → Poisson. If X ~ B(n, p) with n large and p small (roughly n > 50 and np < 5), then X ≈ Po(np). No continuity correction is needed: both are discrete.

Poisson → Normal. If λ is large (λ > 15), then X ≈ N(λ, λ). This is discrete to continuous, so use a continuity correction.

Conditions B(n, p) ≈ Po(np): n > 50, np < 5    Po(λ) ≈ N(λ, λ): λ > 15, continuity correction
Worked Example 1

1.5% of items are faulty. Use a suitable approximation to find the probability that a batch of 200 contains at most 2 faulty items.

Worked Example 2
Exam habit
Memorise
Formula

e−λλr/r!

Mean = variance
Po → N
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