Summary — What This Chapter Covers
- Capacitance C = Q/V, unit farad (F = C V−1); defined for parallel-plate capacitors and isolated spheres.
- Parallel: C = C1 + C2 + …; series: 1/C = 1/C1 + 1/C2 + ….
- Energy stored W = ½QV = ½CV2 = area under the V–Q graph.
- Discharge: x = x0 e−t/RC for Q, V or I; time constant τ = RC.
1. Capacitors and Capacitance
19.1
C = Q/V
A parallel-plate capacitor has two conducting plates separated by an insulator. When charged, one plate holds +Q and the other −Q; “the charge on the capacitor” means Q. Capacitance is the charge stored per unit potential difference. For an isolated spherical conductor, V is its potential relative to infinity (zero), so a sphere of radius r has C = 4πε0r.
Parallel: each capacitor has the same p.d., and the total charge is the sum: Q = Q1 + Q2 gives C = C1 + C2. Series: each capacitor carries the same charge Q, and the p.d.s add: V = V1 + V2, so Q/C = Q/C1 + Q/C2 and 1/C = 1/C1 + 1/C2. These are the reverse of the resistor rules.
Capacitance
C = Q/V parallel C = C1 + C2 + … series 1/C = 1/C1 + 1/C2 + …
Worked Example
A 2.0 μF and a 3.0 μF capacitor are in series, and this pair is in parallel with a 4.0 μF capacitor. Find the total capacitance and the charge stored on the 470 μF capacitor in a separate 12 V circuit.
Practice Question
Find the capacitance of an isolated metal sphere of radius 0.10 m.
2. Energy Stored in a Capacitor
19.2
Area under V–Q
Charging moves charge against the p.d. already on the plates, so work is done. On a graph of p.d. V against charge Q (a straight line through the origin, gradient 1/C), the work done moving a small charge ΔQ is VΔQ, a thin strip. The total energy is the area under the line: a triangle, ½QV.
When a capacitor is charged from a battery of e.m.f. V, the battery supplies QV but the capacitor stores only ½QV; the other half is dissipated in the circuit resistance.
Energy stored
W = ½QV = ½CV2 = Q2/(2C)
Worked Example
Find the energy stored in a 470 μF capacitor charged to 12 V.
3. Discharging a Capacitor
19.3
Exponential decay, τ = RC
time constant
Taking logs gives ln x = ln x0 − t/RC, a straight line with gradient −1/RC, a common way to find RC experimentally. The time to halve is τ ln 2 = 0.693RC.
Discharge
0
−t/RC
Memorise