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AS Level · Physics 9702

Capacitance

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  Cambridge International AS & A Level Physics (9702)

Capacitance

The big idea: A capacitor stores separated charge, and so stores energy. Charge is proportional to p.d., the energy is the area under the V–Q graph, and discharge through a resistor is exponential with time constant RC.

Summary — What This Chapter Covers
  • Capacitance C = Q/V, unit farad (F = C V−1); defined for parallel-plate capacitors and isolated spheres.
  • Parallel: C = C1 + C2 + …; series: 1/C = 1/C1 + 1/C2 + ….
  • Energy stored W = ½QV = ½CV2 = area under the V–Q graph.
  • Discharge: x = x0 e−t/RC for Q, V or I; time constant τ = RC.
1. Capacitors and Capacitance
19.1

C = Q/V

A parallel-plate capacitor has two conducting plates separated by an insulator. When charged, one plate holds +Q and the other −Q; “the charge on the capacitor” means Q. Capacitance is the charge stored per unit potential difference. For an isolated spherical conductor, V is its potential relative to infinity (zero), so a sphere of radius r has C = 4πε0r.

Parallel: each capacitor has the same p.d., and the total charge is the sum: Q = Q1 + Q2 gives C = C1 + C2. Series: each capacitor carries the same charge Q, and the p.d.s add: V = V1 + V2, so Q/C = Q/C1 + Q/C2 and 1/C = 1/C1 + 1/C2. These are the reverse of the resistor rules.

Capacitance C = Q/V    parallel C = C1 + C2 + …    series 1/C = 1/C1 + 1/C2 + …
Worked Example

A 2.0 μF and a 3.0 μF capacitor are in series, and this pair is in parallel with a 4.0 μF capacitor. Find the total capacitance and the charge stored on the 470 μF capacitor in a separate 12 V circuit.

Practice Question

Find the capacitance of an isolated metal sphere of radius 0.10 m.

2. Energy Stored in a Capacitor
19.2

Area under V–Q

Charging moves charge against the p.d. already on the plates, so work is done. On a graph of p.d. V against charge Q (a straight line through the origin, gradient 1/C), the work done moving a small charge ΔQ is VΔQ, a thin strip. The total energy is the area under the line: a triangle, ½QV.

When a capacitor is charged from a battery of e.m.f. V, the battery supplies QV but the capacitor stores only ½QV; the other half is dissipated in the circuit resistance.

Energy stored W = ½QV = ½CV2 = Q2/(2C)
Worked Example

Find the energy stored in a 470 μF capacitor charged to 12 V.

3. Discharging a Capacitor
19.3

Exponential decay, τ = RC

time constant

Taking logs gives ln x = ln x0 − t/RC, a straight line with gradient −1/RC, a common way to find RC experimentally. The time to halve is τ ln 2 = 0.693RC.

Discharge 0 −t/RC
Worked Example
Memorise
Energy
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