Library › Physics 9702 › Alternating Currents
AS Level · Physics 9702

Alternating Currents

Revise Alternating Currents for Physics 9702 (AS Level) — revision notes and instant AI marking.

📖 Revision notes · preview
  Cambridge International AS & A Level Physics (9702)

Alternating Currents

The big idea: An alternating current reverses direction periodically. Its r.m.s. value is the steady current that would give the same power, and diodes plus a capacitor turn it into a nearly steady direct current.

Summary — What This Chapter Covers
  • Period, frequency and peak value; x = x0 sin ωt with ω = 2πf.
  • Mean power in a resistor = half the peak power for a sinusoidal a.c.
  • Ir.m.s. = I0/√2 and Vr.m.s. = V0/√2.
  • Half-wave rectification: one diode. Full-wave: four diodes in a bridge.
  • A smoothing capacitor reduces ripple; larger C or larger load R (larger RC) gives less ripple.
1. Characteristics of Alternating Currents
21.1

Peak and r.m.s.

A sinusoidal alternating current or voltage is described by x = x0 sin ωt, where x0 is the peak value, the period T is the time for one cycle and the frequency f = 1/T, with ω = 2πf.

The power in a resistor is P = I2R. Its peak is I02R, and the average of sin2 over a cycle is ½, so the mean power is half the maximum power. The root-mean-square value is the steady direct current that would dissipate the same mean power in a resistor: Ir.m.s.2R = ½I02R, so Ir.m.s. = I0/√2. Mains voltages are quoted as r.m.s. values.

A.c. relations x = x0 sin ωt    Ir.m.s. = I0/√2    Vr.m.s. = V0/√2    ⟨P⟩ = ½P0 = Vr.m.s.Ir.m.s.
Worked Example

A supply is V = 325 sin(100πt) volts and is connected to a 50 Ω resistor. Find the frequency, the r.m.s. voltage and the mean power.

2. Rectification and Smoothing
21.2

From a.c. to steady d.c.

A diode conducts in one direction only. Half-wave rectification: a single diode in series with the load passes only the positive half-cycles; the output is a series of positive humps with gaps between them. Full-wave rectification: a bridge of four diodes routes the current through the load in the same direction on both half-cycles; two diodes conduct on each half-cycle, and the output is continuous positive humps at twice the supply frequency.

Smoothing: ripple

Worked Example

A full-wave rectified 50 Hz supply peaks at 12 V and is smoothed by a 470 μF capacitor across a 2.0 kΩ load. Estimate the ripple voltage.

Practice Question
Memorise
Sinusoid

x = x0 sin ωt

R.m.s.

x0/√2

Power
Smoothing
🔓 Read the full Alternating Currents note → You're seeing the preview · sign in to read it all
What's inside
📖 Revision notes 🎯 Learn mode ✦ AI flashcards ✓ Instant AI marking 🧊 3D explorers 🧪 Experiments & simulations 📈 Progress tracking
📄 Practise Alternating Currents with Physics 9702 past papers Every paper with its mark scheme — answer online, marked instantly. Open →

Read the full Alternating Currents notes free

That's the preview — create a free account to read the rest, plus flashcards and practice questions with instant AI marking. No credit card.

Unlock the full notes free →

More Physics topics