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Nuclear Physics

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  Cambridge International AS & A Level Physics (9702)

Nuclear Physics

The big idea: A nucleus weighs less than its separate nucleons; the missing mass is the binding energy, E = c²Δm. Radioactive decay is random and spontaneous, but large numbers of nuclei decay exponentially.

Summary — What This Chapter Covers
  • E = mc2; energy released in a reaction E = c2Δm.
  • Mass defect: the difference between the total mass of separate nucleons and the mass of the nucleus. Binding energy: energy to separate a nucleus into its nucleons.
  • Binding energy per nucleon peaks near iron-56; fusion of light nuclei and fission of heavy nuclei both increase it and release energy.
  • Decay is spontaneous and random; A = λN; λ = 0.693/t½.
  • x = x0e−λt for activity, undecayed nuclei or count rate.
1. Mass Defect and Nuclear Binding Energy
23.1

E = c²Δm

Mass and energy are equivalent: E = mc2. Nuclear equations balance nucleon number (top) and proton number (bottom), for example 147N + 42He → 178O + 11H.

The mass defect of a nucleus is the difference between the total mass of its separate protons and neutrons and the mass of the nucleus. The binding energy is the energy needed to separate a nucleus completely into its individual nucleons; it equals c2 × mass defect.

The graph of binding energy per nucleon against nucleon number rises steeply for light nuclei, peaks at about 8.8 MeV near A = 56 (iron), then falls slowly. Higher binding energy per nucleon means a more stable nucleus. Fusion is the joining of two light nuclei into a heavier one; fission is the splitting of a heavy nucleus (usually after absorbing a neutron) into two lighter nuclei and a few neutrons. Both move towards the peak, so the products have greater total binding energy, less mass, and energy is released.

Mass–energy E = mc2    binding energy = c2Δm    1 u = 1.66 × 10−27 kg
Worked Example

A helium-4 nucleus has mass 4.00151 u. A proton is 1.00728 u and a neutron 1.00867 u. Find the binding energy and the binding energy per nucleon in MeV.

Practice Question

Find the energy released in the fusion reaction 21H + 31H → 42He + 10n. Masses: 2.01410 u, 3.01605 u, 4.00260 u, 1.00867 u.

2. Radioactive Decay
23.2

A = λN

Measured count rates fluctuate around an average: evidence that decay is random (you cannot predict which nucleus will decay next, or when). It is also spontaneous: it is not affected by external conditions such as temperature or pressure.

activity −1 decay constant half-life ½

0 −λt 0 ½

Decay A = λN    λ = 0.693/t½    x = x0e−λt
Worked Example

15

Memorise
Mass–energy

E = c2Δm

Binding energy
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