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Group 17

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  Cambridge International AS & A Level Chemistry (9701)

Group 17

The big idea: The halogens are oxidising agents because each atom needs one more electron. Down the group the atoms get larger, so they attract electrons less strongly: the elements become weaker oxidising agents, the halide ions become stronger reducing agents, and the H–X bonds get weaker.

Summary — What This Chapter Covers
  • Cl₂ pale green gas, Br₂ red-brown liquid, I₂ grey-black solid (purple vapour). Volatility decreases down the group as id-id forces increase.
  • X–X bond strength: Cl–Cl > Br–Br > I–I.
  • Oxidising power: Cl₂ > Br₂ > I₂. Reactivity with hydrogen decreases down the group.
  • Thermal stability of HX: HCl > HBr > HI, because the H–X bond gets weaker.
  • Reducing power of halide ions: I⁻ > Br⁻ > Cl⁻, shown by their reactions with concentrated H₂SO₄.
  • Silver halides: AgCl white, AgBr cream, AgI yellow; tell them apart with aqueous ammonia.
  • Chlorine disproportionates in cold and in hot NaOH, and kills bacteria in water via HOCl and ClO⁻.
1. Physical Properties of the Group 17 Elements
Colour and volatility

Cl₂, Br₂, I₂

HalogenState at room temperatureColourBoiling point / °C
Chlorine, Cl₂GasPale green (yellow-green)−34
Bromine, Br₂LiquidRed-brown liquid, orange-brown vapour59
Iodine, I₂SolidGrey-black solid, purple vapour184

Volatility decreases down the group. The molecules have more electrons, so the instantaneous dipole–induced dipole forces between them are stronger and more energy is needed to separate them.

Bond strength

Why the X–X bond weakens

BondCl–ClBr–BrI–I
Bond energy / kJ mol⁻¹242193151

Down the group the atoms are larger, so the bond is longer and the bonding pair is further from the nuclei and more shielded. The attraction between the nuclei and the shared pair is weaker, so the bond energy falls.

Practice Question

Explain why iodine is a solid at room temperature but chlorine is a gas.

2. Chemical Properties of the Halogens and Hydrogen Halides
Halogens as oxidising agents

Cl₂ > Br₂ > I₂

A halogen acts as an oxidising agent by gaining electrons: X₂ + 2e⁻ → 2X⁻. Down the group the atoms are larger and the incoming electron is further from the nucleus and more shielded, so it is attracted less: oxidising power decreases.

A more reactive halogen displaces a less reactive one from a solution of its halide:

KCl(aq)KBr(aq)KI(aq)
Cl₂(aq)–Orange solution: Cl₂ + 2Br⁻ → 2Cl⁻ + Br₂Brown solution: Cl₂ + 2I⁻ → 2Cl⁻ + I₂
Br₂(aq)No reaction–Brown solution: Br₂ + 2I⁻ → 2Br⁻ + I₂
I₂(aq)No reactionNo reaction–

Adding a non-polar solvent (e.g. cyclohexane) helps: Br₂ is orange and I₂ is purple in it.

Reactions with hydrogen

H₂ + X₂ → 2HX

HalogenReaction with hydrogen
Cl₂Explosive in sunlight (or a flame): H₂ + Cl₂ → 2HCl
Br₂Needs heating (about 300 °C) with a platinum catalyst: H₂ + Br₂ → 2HBr
I₂Slow and incomplete even with heat and a catalyst: H₂ + I₂ ⇌ 2HI

Reactivity decreases down the group: the halogens are weaker oxidising agents and the H–X bond formed is weaker, so less energy is released (less exothermic).

Thermal stability of hydrogen halides

Bond strength decides

BondH–ClH–BrH–I
Bond energy / kJ mol⁻¹
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Also in the full note
  • Testing for halides
  • The reducing-power test
  • Two disproportionations
  • Killing bacteria
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