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AS Level · Chemistry 9701

Halogen Compounds

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  Cambridge International AS & A Level Chemistry (9701)

Halogen Compounds

The big idea: The C–X carbon is δ+, so nucleophiles attack it and swap the halogen for OH, CN or NH2. Change the solvent from water to ethanol and the same OH− removes HX instead. How fast the halogen leaves depends on the strength of the C–X bond.

Summary — What This Chapter Covers
  • Halogenoalkanes come from alkanes (free radical), alkenes (electrophilic addition) or alcohols (substitution).
  • Primary, secondary and tertiary halogenoalkanes.
  • Nucleophilic substitution with NaOH(aq), KCN in ethanol, NH3 in ethanol and AgNO3(aq) in ethanol.
  • Elimination with NaOH in ethanol gives an alkene.
  • SN1 and SN2 mechanisms; reactivity RI > RBr > RCl, set by C–X bond strength.
1. Halogenoalkanes
15.1

Making halogenoalkanes

  • From an alkane: Cl2 or Br2 in UV light (free-radical substitution), e.g. C2H6 + Br2 → C2H5Br + HBr.
  • From an alkene: X2 or HX(g) at room temperature (electrophilic addition).
  • From an alcohol (substitution of –OH):
    • HX(g), or KCl with concentrated H2SO4 or H3PO4 (makes HCl in the flask): ROH + HCl → RCl + H2O
    • PCl3 and heat: 3ROH + PCl3 → 3RCl + H3PO3
    • PCl5 at room temperature: ROH + PCl5 → RCl + POCl3 + HCl (steamy fumes)
    • SOCl2: ROH + SOCl2 → RCl + SO2 + HCl (both by-products are gases, so the product is easy to separate)
Classification

Count the carbon atoms bonded to the carbon carrying the halogen: one (or none) = primary, e.g. 1-bromobutane; two = secondary, e.g. 2-bromobutane; three = tertiary, e.g. 2-bromo-2-methylpropane.

15.1

Nucleophilic substitution and elimination

Reagent and conditionsProduct (from bromoethane)Type
NaOH(aq), heat under refluxCH3CH2OH, ethanolnucleophilic substitution
KCN in ethanol, heat under refluxCH3CH2CN, propanenitrile (chain gains one C)nucleophilic substitution
excess NH3 in ethanol, heated under pressure (sealed tube)CH3CH2NH2, ethylaminenucleophilic substitution
AgNO3(aq) in ethanol, warmethanol + Br−, then AgBr(s)nucleophilic substitution (hydrolysis by water)
NaOH in ethanol, heatCH2=CH2, etheneelimination
Key equations CH3CH2Br + OH− → CH3CH2OH + Br−
CH3CH2Br + CN− → CH3CH2CN + Br−
CH3CH2Br + 2NH3 → CH3CH2NH2 + NH4Br
CH3CH2Br + NaOH → CH2=CH2 + NaBr + H2O  (ethanolic)

Identifying the halogen. Warm the halogenoalkane with aqueous silver nitrate in ethanol (ethanol lets the two mix). Water slowly substitutes the halogen and the halide ion released forms a precipitate: AgCl white, AgBr cream, AgI yellow.

15.1

SN2 and SN1 mechanisms

SN2 (one step, two species in the rate-determining step). The nucleophile’s lone pair attacks the δ+ carbon from the side opposite the halogen; at the same moment the C–X bond breaks heterolytically and X leaves as X−. The transition state has the nucleophile and the halogen both partly bonded to carbon, with a negative charge spread over it, drawn in square brackets.

SN1 (two steps, one species in the rate-determining step). Step 1 (slow): the C–X bond breaks heterolytically to give a carbocation and X−. Step 2 (fast): the nucleophile attacks the planar carbocation.

  • Primary SN2
  • Tertiary SN1 N
  • Secondary
Memorise
Reactivity
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