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Electrochemistry (A Level)

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  Cambridge International AS & A Level Chemistry (9701)

Electrochemistry (A Level)

The big idea: This builds on the AS chapter Electrochemistry. Electrode potentials put every redox half-equation on one scale against the hydrogen electrode, so you can predict cell voltages, electrode polarity, which reactions are feasible and what forms in electrolysis. Faraday’s constant turns charge into moles.

Summary — What This Chapter Covers
  • Predict electrolysis products from state, E⦵ and concentration.
  • F = Le; Q = It; masses and volumes liberated; finding L by electrolysis.
  • Standard electrode and cell potentials, the standard hydrogen electrode, and how E⦵ is measured.
  • E⦵cell for polarity, electron flow and feasibility; oxidising and reducing strength; redox equations.
  • Concentration effects and the Nernst equation; ΔG⦵ = −nE⦵cellF.
1. Electrolysis
24.1

Predicting the products

Molten electrolyte: only the compound’s own ions are present. The metal forms at the cathode (−) and the non-metal at the anode (+). Molten PbBr2 gives Pb and Br2.

Aqueous electrolyte: water also provides H+ and OH−, so the ions compete.

  • Cathode: the species with the more positive E⦵ is reduced. Metals below hydrogen (Cu2+/Cu +0.34 V, Ag+/Ag +0.80 V) are deposited. For reactive metals (Na, K, Mg, Al…) hydrogen is given off instead.
  • Anode (inert electrode): oxygen is given off from water/OH− unless a halide is present. Br− and I− give Br2 and I2. Cl− gives Cl2 when concentrated, but mainly O2 when dilute. SO42− and NO3− are not discharged.
  • Concentration matters because it shifts electrode potentials: a high [Cl−] makes oxidation of Cl− easier than that of water.
Electrolyte (inert electrodes)CathodeAnode
concentrated NaCl(aq)H2Cl2
dilute NaCl(aq)H2mainly O2
CuSO4(aq)CuO2
dilute H2SO4H2O2

Quantitative electrolysis

The Faraday constant, F, is the charge on one mole of electrons: F = Le = 6.02 × 1023 × 1.60 × 10−19 = 9.65 × 104 C mol−1.

Charge and moles F = Le    Q = It    moles of electrons = Q/F
Worked Example

A current of 0.500 A passes through CuSO4(aq) for 30.0 minutes. Calculate the mass of copper deposited. (Ar Cu = 63.5, F = 96 500 C mol−1)

Worked Example

Dilute H2SO4 is electrolysed with 2.00 A for 965 s. Calculate the volume of O2 at the anode at room conditions (24.0 dm3 mol−1).

Finding the Avogadro constant by electrolysis
  1. Weigh a clean, dry copper cathode. Set up two copper electrodes in CuSO4(aq) in series with an ammeter, a variable resistor and a d.c. supply.
  2. Pass a constant, measured current for a measured time (keep I steady with the variable resistor).
  3. Remove the cathode, wash with water then propanone, dry and reweigh. The mass gained is copper deposited.
  4. Q = It; n(e−) = 2 × mass/63.5; F = Q/n(e−); L = F/e.
Worked Example

A current of 0.200 A for 60.0 minutes increases the mass of the copper cathode by 0.237 g. Calculate L. (e = 1.60 × 10−19 C)

2. Standard Electrode Potentials
24.2

Definitions

Standard electrode (reduction) potential, E⦵ −3

Standard cell potential, E⦵cell

The standard hydrogen electrode

−3 + −3 + − 2 ⦵

⦵

⦵

  • ⦵
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Also in the full note
  • Measuring E⦵
  • Using E⦵ values
  • Effect of concentration; the Nernst equation
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