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Group 2 (A Level)

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  Cambridge International AS & A Level Chemistry (9701)

Group 2 (A Level)

The big idea: This builds on the AS chapter Group 2. Down the group the cation stays 2+ but gets bigger. That one change explains why carbonates and nitrates need more heat to decompose, and why hydroxides get more soluble while sulfates get less soluble.

Summary — What This Chapter Covers
  • Group 2 carbonates and nitrates decompose on heating; thermal stability increases down the group.
  • The explanation is polarisation: a small 2+ ion with a high charge density distorts the electron cloud of the large carbonate or nitrate ion.
  • ΔH⦵sol depends on the balance between lattice energy and the enthalpies of hydration of the ions.
  • Down the group, hydroxides become more soluble and sulfates become less soluble.
1. Thermal Stability and Solubility of Group 2 Compounds
27.1

Thermal decomposition of carbonates and nitrates

Decomposition on heating MCO3(s) → MO(s) + CO2(g)
2M(NO3)2(s) → 2MO(s) + 4NO2(g) + O2(g)

Nitrates give off brown fumes of NO2 and a gas (O2) that relights a glowing splint. Carbonates give off CO2, which turns limewater milky.

Down the group (Mg → Ba), a higher temperature is needed for decomposition: thermal stability increases.

Explanation
  • All Group 2 cations have a 2+ charge, but the ionic radius increases down the group.
  • So the charge density of the cation decreases down the group.
  • A cation with a high charge density (Mg2+) polarises (distorts) the electron cloud of the large CO32− or NO3− anion more.
  • This weakens the C–O (or N–O) bonds in the anion, so less energy is needed to break them and form the oxide.
  • Larger cations (Ba2+) polarise the anion less, so more heat is needed.
Practice Question

Explain why magnesium carbonate decomposes at a lower temperature than barium carbonate.

Solubility and enthalpy change of solution

The enthalpy change of solution, ΔH⦵sol, is the enthalpy change when 1 mol of an ionic solid dissolves in enough water to give an infinitely dilute solution. Think of it in two stages: separate the lattice into gaseous ions (the reverse of the lattice energy, endothermic), then hydrate the ions (exothermic).

Energy cycle ΔH⦵sol = ΔH⦵hyd(cation) + ΔH⦵hyd(anion) − ΔH⦵latt

The more exothermic (or the less endothermic) ΔH⦵sol is, the more soluble the compound tends to be.

Down the group, as the cation gets larger, both the lattice energy and the hydration enthalpy of the cation become less exothermic. Which one falls faster decides the trend.

Hydroxides, M(OH)2Sulfates, MSO4
Trend down the groupSolubility increases (Mg(OH)2 sparingly soluble, Ba(OH)2 fairly soluble)Solubility decreases (MgSO4 soluble, BaSO4 insoluble)
Lattice energyOH− is small, so the inter-ionic distance depends strongly on the cation. Lattice energy becomes much less exothermic as the cation grows.SO42− is large, so the inter-ionic distance hardly changes. Lattice energy changes only a little.
Hydration enthalpy of cationBecomes less exothermic, but by less than the lattice energy.Becomes less exothermic, by more than the lattice energy.
Result for ΔH⦵sol Becomes more exothermic → more soluble
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