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Nitrogen Compounds (A Level)

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  Cambridge International AS & A Level Chemistry (9701)

Nitrogen Compounds (A Level)

The big idea: This builds on the AS chapter Nitrogen Compounds. The lone pair on nitrogen drives this whole chapter: it makes amines bases and nucleophiles. When the lone pair is delocalised (into a benzene ring, or across a C=O group) it is less available, which is why phenylamine is a weaker base and amides are barely basic at all.

Summary — What This Chapter Covers
  • Amines are made from halogenoalkanes with NH3 or amines, and by reducing amides or nitriles.
  • Amines react with acyl chlorides to give amides; their aqueous solutions are basic.
  • Phenylamine is made from nitrobenzene; it reacts with Br2(aq) and with HNO2 to form a diazonium salt.
  • Base strength: ethylamine > ammonia > phenylamine.
  • Diazonium salts couple with phenol to form azo dyes.
  • Amides are hydrolysed by acid or alkali, reduced by LiAlH4, and are much weaker bases than amines.
  • Amino acids form zwitterions, link through peptide bonds and separate by electrophoresis.
1. Primary and Secondary Amines
34.1

Making amines

MethodReagents and conditionsExample
Halogenoalkane + ammoniaNH3 in ethanol, heated under pressure (sealed tube)CH3CH2Br + NH3 → CH3CH2NH2 + HBr
Halogenoalkane + primary amineAmine in ethanol, heated in a sealed tube / under pressureCH3CH2Br + CH3CH2NH2 → (CH3CH2)2NH + HBr
Reduction of an amideLiAlH4 in dry etherCH3CONH2 + 4[H] → CH3CH2NH2 + H2O
Reduction of a nitrileLiAlH4 in dry ether, or H2 with a Ni catalystCH3CN + 4[H] → CH3CH2NH2

The halogenoalkane route gives a mixture: the amine product is itself a nucleophile and can react again to give secondary and tertiary amines and a quaternary ammonium salt. A large excess of ammonia favours the primary amine. The HBr formed reacts with excess NH3 or amine to give a salt.

Amines with acyl chlorides

Ammonia or an amine reacts with an acyl chloride at room temperature in a condensation reaction to give an amide and HCl: CH3COCl + CH3CH2NH2 → CH3CONHCH2CH3 + HCl.

Basicity

The lone pair on N accepts a proton, so aqueous amines are alkaline: CH3CH2NH2 + H2O ⇌ CH3CH2NH3+ + OH−. They are weak bases (the equilibrium lies to the left). With acids they form salts: CH3CH2NH2 + HCl → CH3CH2NH3+Cl−.

Practice Question

Give two different ways of making propylamine, CH3CH2CH2NH2, naming the starting organic compound for each.

2. Phenylamine and Azo Compounds
34.2

Making phenylamine

  1. Nitrate benzene (conc HNO3 + conc H2SO4, 25–60 °C) to nitrobenzene.
  2. Reduce nitrobenzene by heating with tin and concentrated HCl: C6H5NO2 + 6[H] → C6H5NH2 + 2H2O. In the acid the product is present as the salt C6H5NH3+.
  3. Add NaOH(aq) to release the free amine: C6H5NH3+ + OH− → C6H5NH2 + H2O.
Reactions of phenylamine
  • Br2(aq), room temperature: decolourised, white precipitate of 2,4,6-tribromophenylamine. C6H5NH2 + 3Br2 → C6H2Br3NH2 + 3HBr. As with phenol, the N lone pair is delocalised into the ring, activating it.
  • HNO2 (NaNO2 + dilute HCl) below 10 °C: benzenediazonium chloride. C6H5NH2 + HNO2 + HCl → C6H5N2+Cl− + 2H2O. Warming this with water gives phenol: C6H5N2+Cl− + H2O → C6H5OH + N2 + HCl.

Basicity: ammonia, ethylamine and phenylamine

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Also in the full note
  • Azo compounds
  • Making and reacting amides
  • Zwitterions and the isoelectric point
  • Electrophoresis
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