Simultaneous Equations
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Simultaneous Equations
The big idea: when you've got two unknowns hiding in two clues, you combine the clues — by eliminating one letter or substituting one equation into the other — until only one unknown is left standing.
- Linear simultaneous equations only have
xandyto the power 1 (nox²,y², orxy). Solve them with the elimination method or the substitution method. - Quadratic (non-linear) simultaneous equations have an
x²,y², orxyin at least one equation. These must be solved by substitution — you always substitute the linear equation into the quadratic one, never the other way round. - Graphically, solving simultaneous equations = finding where two graphs cross. The coordinates of the crossing point(s) are the solution(s).
- Quadratic simultaneous equations can have 0, 1, or 2 solutions — because a line can miss a curve, touch it (tangent), or cut through it twice.
- Worded problems are just simultaneous equations wearing a costume — the hard part is translating the words into two equations correctly.
- Always check your final answers in both original equations. This catches almost every sign error.
Two unknowns need two clues
Imagine someone tells you: "I'm thinking of two numbers. Their sum is 11." You genuinely can't figure out what those numbers are — there are infinite pairs that sum to 11 (1 and 10, 2 and 9, 5.5 and 5.5...). One clue for two unknowns just isn't enough information.
But now they tell you a second clue: "...and their difference is 3." Suddenly you can pin down exactly one pair of numbers. That's the whole idea behind simultaneous equations: when you have two unknowns, you need two equations (two independent pieces of information) to find unique values for both.
"Simultaneous" literally means "at the same time" — you're looking for the pair of values
(an x and a y) that make both equations true
simultaneously, not just one of them.
Linear vs. Quadratic — how to tell them apart instantly
Look at the powers of x and y in each equation:
| Type | What you'll see | Example |
|---|---|---|
| Linear | Only x and y — no squares, no xy | 3x + 2y = 11 |
| Quadratic / Non-linear | An x², y², or an xy term somewhere | x² + y² = 25 |
If you graph a linear equation, you get a straight line (linear = line — easy way to remember it).
If you graph a quadratic equation like x² + y² = 25 you get a curve
(in that case, a circle). This matters because two straight lines cross at most once,
but a line and a curve can cross 0, 1, or 2 times — which is exactly why quadratic
simultaneous equations can give you two different answer-pairs.
The core idea: cancel one letter out
Elimination works like this: if two equations both contain, say, 6x, and you
subtract one equation from the other, the x's vanish completely (6x − 6x = 0).
You're left with a single equation in a single unknown — which you can just solve directly.
x
(or y) match.2. If the matching terms have the same sign → subtract. If they have different signs → add.
3. Solve the resulting one-unknown equation.
4. Substitute that value back into either original equation to find the other unknown.
5. Check both original equations.
Worked example — start to finish
x-terms: −4x (from the new ①) and +4x (from ②) — different signs, so we add.Swap a letter for an expression
Substitution takes a different route to the same destination. Instead of cancelling a term,
you rearrange one equation so that y (or x) is completely on its own —
"the subject" of the equation. Then, wherever y appears in the other
equation, you replace it with that expression. This turns two equations with two unknowns
into one equation with just one unknown.
y = ... (or x = ...).2. Substitute that expression into the other equation, wrapping it in brackets.
3. Solve the resulting one-unknown equation.
4. Substitute that value back into your rearranged equation to find the other unknown.
5. Check both original equations.
Worked example
y = 1 − 9x). But here's the
crucial bit: for quadratic simultaneous equations, you have no
choice — substitution is the only method that works, so it's worth being fully
comfortable with it now.
The solution is where lines cross
Every equation in x and y can be drawn as a graph. A linear equation
draws a straight line; every point on that line makes the equation true. If you draw
two equations on the same axes, then any point where the two graphs intersect
is a point that satisfies both equations at once — which is exactly what "solving
simultaneously" means.
y
| 2x−y=3
| /
| /
| ★(2,1) ← lines cross here
| / \
| / \
|_____/______\____ x
| / 3x+y=7
Reading off the graph: the lines above cross at (2, 1), so the solution to
2x − y = 3 and 3x + y = 7 simultaneously is x = 2, y = 1.
Turning a story into two equations
Worded questions are simultaneous equations in disguise. The skill being tested isn't really the algebra — it's spotting that there are two unknown quantities and two independent pieces of information, and translating each piece of information into an equation. Always start by clearly defining your letters, in words, before writing any equations.
Worked example
Why elimination won't work here
Elimination relies on lining up matching terms and cancelling them by adding or subtracting.
That's only possible when both equations have the same "shape" of terms. Once one equation
has an x² or xy and the other doesn't, there's nothing to match up —
so elimination is off the table. Substitution, however, always works because you're not
trying to match anything; you're replacing a whole variable with an expression, however
complicated that expression is.
Worked example — full method
(x₁, y₁) = (6, 0) and
(x₂, y₂) = (−3.6, −4.8).
Reading the number of solutions from the discriminant
Once you've substituted and simplified down to a quadratic equation (something you'd solve with factorising, completing the square, or the quadratic formula), the discriminant tells you geometrically what's happening between the line and the curve:
| Discriminant | Number of solutions | Geometric meaning |
|---|---|---|
| Positive (b² − 4ac > 0) | 2 solutions | The line cuts through the curve at two points |
| Zero (b² − 4ac = 0) | 1 repeated solution | The line is a tangent — it just touches the curve |
| Negative (b² − 4ac < 0) | 0 real solutions | The line completely misses the curve |
| Term / Rule | What it means |
|---|---|
| Simultaneous equations | Two (or more) equations that must be true at the same time — solved together to find unique values for each unknown. |
| Linear equation | Only powers of 1 for x and y (no x², y², xy). Graphs as a straight line. |
| Quadratic / non-linear | Contains x², y², or xy. Graphs as a curve. |
| Elimination method | Match coefficients, then add (different signs) or subtract (same signs) to cancel one variable. |
| Substitution method | Rearrange one equation for x or y, then substitute that expression into the other equation. |
| Golden rule for quadratics | Always substitute the linear equation into the quadratic one — never the reverse. |
| Graphical solution | Solutions = the coordinates of the point(s) where the two graphs intersect. |
| Tangent case | A repeated root (discriminant = 0) means the line touches the curve at exactly one point. |
| No solution case | A negative discriminant means the line and curve never meet. |
| Checking step | Substitute your final x and y values into both original equations to confirm they work. |
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