AS Level · Pure Mathematics 1 P1

Series

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 1

Series

The big idea: Arithmetic progressions add the same amount each time, geometric progressions multiply by the same amount, and the binomial theorem counts how the terms of (a + b)n combine.

Summary — What This Chapter Covers
  • (a + b)n for positive integer n, using nCr = n!/(r!(n − r)!).
  • AP: un = a + (n − 1)d and Sn = ½n[2a + (n − 1)d].
  • GP: un = arn−1 and Sn = a(1 − rn)/(1 − r).
  • A GP converges if |r| < 1, and then S∞ = a/(1 − r).
  • a, b, c are in AP if 2b = a + c, and in GP if b2 = ac.
1. The Binomial Expansion
Binomial

(a + b)n for positive integers n

The term in br is nCran−rbr. Put any coefficient of x inside the bracket with x when you raise it to a power: (3x)3 = 27x3, not 3x3. For "term independent of x", write the general term and make the power of x zero.

Binomial theorem (a + b)n = an + nC1an−1b + nC2an−2b2 + … + bn,   nCr = n!/(r!(n − r)!)
Worked Example

Find the coefficient of x3 in the expansion of (2 + 3x)5.

Practice Question 1

Find the first three terms, in ascending powers of x, of (1 − 2x)6.

Practice Question 2

Find the term independent of x in (x + 2/x)6.

2. Arithmetic Progressions
AP

Constant difference d

Each term is the previous one plus d. Two pieces of information (two terms, or a term and a sum) give two equations in a and d. "How many terms" questions lead to an inequality in n; n must be a whole number.

AP formulae un = a + (n − 1)d  ·  Sn = ½n[2a + (n − 1)d] = ½n(a + l), l = last term
Worked Example

The 5th term of an AP is 18 and the sum of the first 10 terms is 210. Find a and d.

Practice Question

Find the least number of terms of 3 + 7 + 11 + … needed for the sum to exceed 500.

3. Geometric Progressions and Sum to Infinity
GP

Constant ratio r

Each term is the previous one multiplied by r. If |r| < 1, the terms shrink towards zero and the sum approaches a/(1 − r); if |r| ≥ 1, there is no sum to infinity. Questions often combine an AP and a GP: write each condition as an equation and solve.

GP formulae un = arn−1  ·  Sn = a(1 − rn)/(1 − r)  ·  S∞ = a/(1 − r), |r| < 1
Worked Example
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