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Integration

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  Cambridge International AS & A Level Mathematics 9709 — Pure Mathematics 1

Integration

The big idea: Integration undoes differentiation. The same reverse rule then measures areas under curves and, rotated through 360°, the volumes of solids.

Summary — What This Chapter Covers
  • ∫xn dx = xn+1/(n + 1) + c for n ≠ −1.
  • ∫(ax + b)n dx = (ax + b)n+1/[a(n + 1)] + c for n ≠ −1.
  • Use a known point on a curve to find the constant of integration.
  • Definite integrals give signed area; areas below the x-axis come out negative.
  • Simple improper integrals: an infinite limit, or a function undefined at one limit.
  • Volume about the x-axis: π∫y2 dx; about the y-axis: π∫x2 dy.
1. Indefinite Integration
Reverse differentiation

Add one to the power, divide by the new power

Rewrite roots and fractions as powers first. For a bracket (ax + b)n, integrate as if the bracket were x and then divide by a, the derivative of the inside. If you are given dy/dx and a point on the curve, integrate and substitute the point to find c.

Rules ∫xn dx = xn+1/(n + 1) + c  ·  ∫(ax + b)n dx = (ax + b)n+1/[a(n + 1)] + c  (n ≠ −1)
Worked Example

A curve has dy/dx = √(2x + 1) and passes through (4, 10). Find its equation.

Practice Question 1

Find ∫(3x − 2)4 dx and ∫ 1/(2x + 3)2 dx.

Practice Question 2

Find ∫(6x2 − 4/x3) dx.

2. Definite Integrals and Area
Area

Under a curve, between curves, and to infinity

∫ab f(x) dx = F(b) − F(a). Area between a curve and the x-axis is ∫y dx; if part of the region is below the axis, that part gives a negative value, so find each part separately and add the sizes. Area between two curves is ∫(upper − lower) dx between their intersections. Area against the y-axis is ∫x dy.

An improper integral has an infinite limit, or an integrand that is undefined at a limit. Evaluate with a letter, then see what happens as it tends to the limit: ∫1∞ x−2 dx = [−1/x]1∞ = 0 − (−1) = 1, and ∫01 x−½ dx = [2√x]01 = 2.

Worked Example

Find the area enclosed between y = 4x − x2 and y = x.

Worked Example

Find the area between y = x2 − 4x and the x-axis.

Practice Question 1

Evaluate ∫14(2x + 1/√x) dx.

Practice Question 2

Evaluate ∫1∞ x−3 dx.

3. Volumes of Revolution
Volumes

Rotate through 360°

Rotating y = f(x) between x = a and x = b about the x-axis gives a solid of volume π∫y2 dx. About the y-axis, write x2 in terms of y and use π∫x2 dy with y-limits. If the region is not bounded by the axis, subtract: π∫(youter2 − yinner2) dx.

Volumes a b 2 c d 2
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