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Continuous Random Variables

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  Cambridge International AS & A Level Mathematics 9709 — Probability & Statistics 2

Continuous Random Variables

The big idea: For a continuous random variable, probability is area under the density curve: the total area is 1, and every probability, mean and median is an integral.

Summary — What This Chapter Covers
  • A probability density function satisfies f(x) ≥ 0 and ∫f(x) dx = 1 over its domain.
  • P(a < X < b) = ∫ab f(x) dx; P(X = a) = 0.
  • E(X) = ∫x f(x) dx; Var(X) = ∫x2 f(x) dx − [E(X)]2.
  • Median m: ∫ from the lower limit to m of f(x) dx = 0.5. Other percentiles similarly.
  • Domains may be infinite, e.g. f(x) = 3/x4 for x ≥ 1.
1. Probability Density Functions
pdf

Area is probability

A pdf f(x) is defined over a single interval and is zero elsewhere. It is never negative, and the total area under it is 1 — use this to find an unknown constant. Probabilities are areas, so it makes no difference whether inequalities are strict. For an infinite domain, use the limit: ∫1∞ x−4 dx = [−x−3/3]1∞ = 1/3.

The sketch helps: the mode is where f(x) is greatest.

Properties f(x) ≥ 0    ∫f(x) dx = 1    P(a < X < b) = ∫ab f(x) dx
Worked Example

f(x) = kx2 for 0 ≤ x ≤ 3 and 0 otherwise. Find k and P(X < 2).

Practice Question 1

f(x) = k/x4 for x ≥ 1. Find k and P(X > 2).

2. Mean, Variance, Median and Percentiles
Summary measures

Integrals for everything

The mean is ∫x f(x) dx and the variance is ∫x2 f(x) dx minus the square of the mean. The median m splits the area in half: solve ∫ f(x) dx from the lower limit to m = 0.5. The upper quartile q satisfies an area of 0.75 to its left (or 0.25 to its right — often easier for an infinite domain). The cumulative distribution function itself is not required; just integrate the area directly.

Measures E(X) = ∫x f(x) dx    Var(X) = ∫x2 f(x) dx − [E(X)]2    median: ∫am f(x) dx = ½
Worked Example

2

Practice Question 2

4

Memorise
Total area
Mean
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