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Transformation geometry

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  Pearson Edexcel International GCSE Mathematics A (4MA1)

Transformation geometry

The big idea: Each transformation has its own short list of facts that pin it down. Give exactly those facts — no more, no fewer — and the description is complete.

Summary — What This Chapter Covers
  • Rotation: centre, angle, direction (anticlockwise positive, clockwise negative).
  • Reflection: the mirror line, as an equation such as x = 1, y = 2, y = x.
  • Translation: a column vector giving the distance and direction.
  • Rotations, reflections and translations keep length and angle, so the image is congruent.
  • Enlargement: centre and scale factor; angles kept, lengths multiplied.
  • Describe a single transformation fully.
1. Rotations
Foundation & Higher

Centre, angle and direction

A rotation is specified by a centre and an angle. Anticlockwise is a positive angle and clockwise is negative, so −90° means 90° clockwise. Use tracing paper: hold the centre with a pencil point and turn.

About the origin 90° anticlockwise: (x, y) → (−y, x)    180°: (x, y) → (−x, −y)    90° clockwise: (x, y) → (y, −x)
Worked Example

Triangle T has vertices (1, 1), (3, 1) and (1, 2). Rotate T 90° anticlockwise about the origin.

Practice Question 1

Rotate the point (4, 1) through −90° about the centre (2, 0).

2. Reflections
Foundation & Higher

The mirror line

A reflection is specified by a mirror line. Each image point is the same perpendicular distance from the mirror as its object, on the other side. To find a mirror line from an object and image, join a point to its image: the mirror line is the perpendicular bisector of that line.

Mirror line(x, y) maps to
x = a (vertical)(2a − x, y)
y = b (horizontal)(x, 2b − y)
y = x (also written y − x = 0)(y, x)
y = −x(−y, −x)
Worked Example

Reflect the point (4, 1) in (a) the line x = 1, (b) the line y = 2, (c) the line y = x.

Practice Question 2

Point A(1, 2) is reflected to A′(5, 2). Find the equation of the mirror line.

3. Translations and Column Vectors
Foundation & Higher

Slide without turning

A translation moves every point the same distance in the same direction, given by a column vector (x over y): x to the right (negative = left) and y up (negative = down).

Worked Example

Point A(2, 5) is translated to A′(−1, 3). Write down the column vector of the translation.

4. Congruence and Enlargement
Foundation & Higher

What is kept, what changes

Rotations, reflections and translations preserve length and angle, so the image is congruent to the object. An enlargement is specified by a centre and a scale factor; it preserves angles but not lengths, so the image is similar. Only positive scale factors are used, including fractions (a fraction less than 1 makes the shape smaller).

To enlarge from a centre C with scale factor k: for each vertex, multiply its distance from C (horizontally and vertically) by k. To find the centre, join corresponding vertices with straight lines: they meet at the centre.

Enlargement image point = C + k × (P − C)    image length = k × object length
Worked Example
Practice Question 3
Memorise
Rotation
Reflection
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