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Graphs in practical situations

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  Cambridge O Level Mathematics (Syllabus D) 4024

Graphs in practical situations

The big idea: A real-life graph turns a situation into a picture. The gradient is a rate (speed on a distance–time graph, acceleration on a speed–time graph), and the area under a speed–time graph is the distance travelled.

Summary — What This Chapter Covers
  • Use and interpret travel graphs and conversion graphs.
  • Draw graphs from given data.
  • Apply rate of change to distance–time and speed–time graphs, including acceleration and deceleration.
  • Calculate distance travelled as the area under a speed–time graph (linear sections only).
  • Estimate and interpret the gradient of a tangent at a point on a curve.
1. Distance–Time (Travel) Graphs
Syllabus 2.9 · Paper 1 & 2

Gradient = speed

Time is on the horizontal axis and distance from a starting point on the vertical axis. A straight sloping section means constant speed; its gradient is the speed. A horizontal section means the object is stationary. A section sloping down means it is returning towards the start. The steeper the line, the faster the speed.

Worked Example

A travel graph for Omar’s cycle ride is made of straight lines joining these points (time, distance from home): (0900, 0 km), (0930, 15 km), (1000, 15 km), (1045, 0 km).
(a) Find his speed for the first part of the ride. (b) What happened from 0930 to 1000? (c) Find his speed on the way home.

2. Conversion Graphs and Drawing Graphs from Data
Syllabus 2.9 · Paper 1 & 2

Read across, then down

A conversion graph is a straight line, often through the origin. To convert, go from the value on one axis to the line, then across (or down) to the other axis. To draw a graph from a table of data, choose sensible scales, label both axes with units, plot each point accurately and join with a ruler if the relationship is linear.

Practice Question 1

A straight-line conversion graph between dollars (horizontal axis) and dirhams passes through (0, 0) and (50, 183.5).
(a) Use the graph’s gradient to convert $30 to dirhams. (b) A price of 2202 dirhams is off the graph. Convert it to dollars.

3. Speed–Time Graphs
Syllabus 2.9 · Paper 1 & 2

Gradient = acceleration; area = distance

On a speed–time graph the gradient is the acceleration (in m/s2). A negative gradient is a deceleration. A horizontal section means constant speed. The area under the graph is the distance travelled: split it into triangles, rectangles and trapezia.

Speed–time graphs acceleration = change in speed ÷ time taken   ·   distance = area under the graph
trapezium area = ½(a + b)h  (not given in the List of formulas: learn it)
Worked Example

A train starts from rest and accelerates steadily to 15 m/s in 10 seconds. It travels at 15 m/s for 30 seconds, then decelerates steadily to rest in 20 seconds.
(a) Find the acceleration. (b) Find the deceleration. (c) Find the total distance travelled. (d) Find the average speed for the whole journey.

Practice Question 2

A car starts from rest and accelerates steadily for 10 s to a speed of V m/s. It then travels at V m/s for 30 s and decelerates steadily to rest in 20 s. The total distance travelled is 900 m. Find V.

4. Tangents and Rates of Change on Curves
Memorise
Speed–time
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  • The gradient at one instant
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